Question Number 118541 by bramlexs22 last updated on 18/Oct/20 $$\:\:\:\int\:\mathrm{tan}\:\left({x}\right).\mathrm{tan}\:\left(\mathrm{2}{x}\right).\mathrm{tan}\:\left(\mathrm{3}{x}\right)\:{dx}\:=\:? \\ $$ Commented by bramlexs22 last updated on 18/Oct/20 $${thank}\:{you}\:{all}\: \\ $$ Answered by Lordose…
Question Number 184061 by mathlove last updated on 02/Jan/23 $$\int\frac{{sin}^{−\mathrm{1}} \sqrt{{x}}−{cos}^{−\mathrm{1}} \sqrt{{x}}}{{sin}^{−\mathrm{1}} \sqrt{{x}}+{cos}^{−\mathrm{1}} \sqrt{{x}}}{dx}=? \\ $$ Answered by SEKRET last updated on 02/Jan/23 $$\:\:\:\boldsymbol{\mathrm{arcsin}}\left(\sqrt{\boldsymbol{\mathrm{x}}}\:\right)+\:\boldsymbol{\mathrm{arccos}}\left(\sqrt{\boldsymbol{\mathrm{x}}}\:\right)=\:\frac{\boldsymbol{\pi}}{\mathrm{2}} \\…
Question Number 52988 by Joel578 last updated on 16/Jan/19 $$\int\:\frac{{x}^{\mathrm{2}} }{\:\sqrt{\mathrm{1}\:+\:{x}^{\mathrm{4}} }}\:{dx} \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 16/Jan/19 $$\int{x}^{\mathrm{2}} ×\left(\mathrm{1}+{x}^{\mathrm{4}} \right)^{\frac{−\mathrm{1}}{\mathrm{2}}} {dx}…
Question Number 118491 by Lordose last updated on 18/Oct/20 $$ \\ $$$$…\:\blacklozenge\mathrm{Advanced}\:\mathrm{Calculus}\blacklozenge… \\ $$$$ \\ $$$$\mathrm{Evaluate}:: \\ $$$$ \\ $$$$\Omega\:=\:\int_{\mathrm{0}} ^{\:\infty} \frac{\mathrm{sec}\theta}{\:\sqrt{\mathrm{4tan}^{\mathrm{2}} \theta+\mathrm{5}}}\mathrm{d}\theta \\ $$$$…
Question Number 118478 by mathmax by abdo last updated on 17/Oct/20 $$\mathrm{find}\:\int_{\mathrm{0}} ^{\infty} \:\mathrm{e}^{−\mathrm{2x}} \mathrm{ln}\left(\mathrm{1}+\mathrm{3x}\right)\mathrm{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 52944 by Tawa1 last updated on 15/Jan/19 $$\int_{\:\mathrm{0}} ^{\:\mathrm{1}} \:\:\frac{\boldsymbol{\mathrm{x}}^{\mathrm{3}} \:−\:\mathrm{1}}{\left(\mathrm{1}\:+\:\boldsymbol{\mathrm{x}}^{\mathrm{2}} \right)\:\boldsymbol{\mathrm{ln}}\:\boldsymbol{\mathrm{x}}}\:\:\boldsymbol{\mathrm{dx}} \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 15/Jan/19 $${I}\left({a}\right)=\int_{\mathrm{0}} ^{\mathrm{1}}…
Question Number 118475 by mathmax by abdo last updated on 17/Oct/20 $$\mathrm{calculate}\:\int_{\mathrm{0}} ^{\infty} \:\frac{\mathrm{arctan}\left(\mathrm{2}+\mathrm{x}^{\mathrm{2}} \right)}{\mathrm{x}^{\mathrm{2}} +\mathrm{9}}\mathrm{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 118476 by mathmax by abdo last updated on 17/Oct/20 $$\mathrm{find}\:\int_{−\infty} ^{\infty} \:\frac{\mathrm{arctan}\left(\mathrm{1}+\mathrm{2x}\right)}{\mathrm{x}^{\mathrm{2}} \:+\mathrm{1}}\mathrm{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 183977 by cortano1 last updated on 01/Jan/23 $$\:\int_{\mathrm{0}} ^{\:\infty} \:\frac{{dx}}{{x}^{\mathrm{8}} +{x}^{\mathrm{4}} +\mathrm{1}}\:=?\: \\ $$ Answered by ARUNG_Brandon_MBU last updated on 01/Jan/23 $$\Omega=\int_{\mathrm{0}} ^{\infty}…
Question Number 183976 by cortano1 last updated on 01/Jan/23 $$\:\:\int\:\frac{\mathrm{sin}\:{x}−\sqrt{\mathrm{1}+\mathrm{sin}\:{x}}}{\mathrm{cos}\:{x}−\sqrt{\mathrm{1}+\mathrm{cos}\:{x}}}\:{dx}\:=? \\ $$ Answered by MJS_new last updated on 01/Jan/23 $${t}=\frac{\mathrm{1}+\mathrm{sin}\:\frac{{x}}{\mathrm{2}}}{\mathrm{cos}\:\frac{{x}}{\mathrm{2}}}\Leftrightarrow{x}=\mathrm{2arctan}\:\frac{{t}^{\mathrm{2}} −\mathrm{1}}{\mathrm{2}{t}}\:\rightarrow\:{dx}=\frac{\mathrm{4}{dt}}{{t}^{\mathrm{2}} −\mathrm{1}} \\ $$$$\Rightarrow \\…