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Category: Integration

tan-1-1-x-1-x-dx-

Question Number 120761 by bramlexs22 last updated on 02/Nov/20 tan1(1x1+x)dx? Answered by liberty last updated on 02/Nov/20 Weputx=cosψdx=sinψdψ$$\int\:\mathrm{tan}^{−\mathrm{1}} \:\sqrt{\frac{\mathrm{1}−\mathrm{cos}\:\psi}{\mathrm{1}+\mathrm{cos}\:\psi}}\:\left(−\mathrm{sin}\:\psi\:\mathrm{d}\psi\right)\:= \

dx-a-sin-x-b-cos-x-

Question Number 120758 by bramlexs22 last updated on 02/Nov/20 dxasinx+bcosx Answered by Dwaipayan Shikari last updated on 02/Nov/20 $$\mathrm{2}\int\frac{{dt}}{{a}\left(\frac{\mathrm{2}{t}}{\mathrm{1}+{t}^{\mathrm{2}} }\right)+{b}\left(\frac{\mathrm{1}−{t}^{\mathrm{2}} }{\mathrm{1}+{t}^{\mathrm{2}} }\right)}.\frac{\mathrm{1}}{\mathrm{1}+{t}^{\mathrm{2}} }\:\:\:\:\:\:\:\:\:\:\:\:\:{tan}\frac{{x}}{\mathrm{2}}={t}…