Question Number 119970 by bramlexs22 last updated on 28/Oct/20
Question Number 119960 by mnjuly1970 last updated on 28/Oct/20 Answered by mathmax by abdo last updated on 28/Oct/20 $$\mathrm{A}\:=\int_{\mathrm{0}} ^{\infty} \:\frac{\mathrm{arctanx}}{\left(\mathrm{1}+\mathrm{x}\right)\sqrt{\mathrm{x}}}\mathrm{dx}\:\Rightarrow\mathrm{A}\:=_{\sqrt{\mathrm{x}}=\mathrm{t}} \:\:\int_{\mathrm{0}} ^{\infty} \:\frac{\mathrm{arctan}\left(\mathrm{t}^{\mathrm{2}} \right)}{\left(\mathrm{1}+\mathrm{t}^{\mathrm{2}}…
Question Number 54416 by 951172235v last updated on 03/Feb/19 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 185484 by Mingma last updated on 22/Jan/23 Answered by Ar Brandon last updated on 22/Jan/23 $${I}=\int_{\mathrm{0}} ^{\infty} \frac{{x}^{\mathrm{3}} }{{e}^{\mathrm{3}{x}} −\mathrm{1}}{dx}=\int_{\mathrm{0}} ^{\infty} \frac{{x}^{\mathrm{3}} {e}^{−\mathrm{3}{x}}…
Question Number 119934 by bramlexs22 last updated on 28/Oct/20
Question Number 119930 by Lordose last updated on 28/Oct/20 Answered by mathmax by abdo last updated on 28/Oct/20
Question Number 119920 by bramlexs22 last updated on 28/Oct/20
Question Number 185455 by cortano1 last updated on 22/Jan/23
Question Number 185451 by mathlove last updated on 22/Jan/23 Commented by Frix last updated on 22/Jan/23
Question Number 54376 by Abdo msup. last updated on 02/Feb/19