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Category: Integration

solve-tan-x-tan-x-tan-2x-dx-

Question Number 54756 by Knight last updated on 10/Feb/19 solvetan(xθ)tan(x+θ)tan2xdx Answered by tanmay.chaudhury50@gmail.com last updated on 10/Feb/19 tan2x=tan(x+θ+xθ)$$\:\:\:\:\:\:\:\:\:\:\:\:\:{tan}\mathrm{2}{x}=\frac{{tan}\left({x}+\theta\right)+{tan}\left({x}−\theta\right)}{\mathrm{1}−{tan}\left({x}+\theta\right){tan}\left({x}−\theta\right)} \

dx-1-cos-cos-x-

Question Number 120254 by bramlexs22 last updated on 30/Oct/20 dx1+cosθ.cosx? Answered by TANMAY PANACEA last updated on 30/Oct/20 dxcosθ(secθ+cosx)$$\frac{\mathrm{1}}{{cos}\theta}\int\frac{{dx}}{{sec}\theta+\frac{\mathrm{1}−{tan}^{\mathrm{2}} \frac{{x}}{\mathrm{2}}}{\mathrm{1}+{tan}^{\mathrm{2}} \frac{{x}}{\mathrm{2}}}}…

Question-54701

Question Number 54701 by Meritguide1234 last updated on 09/Feb/19 Answered by behi83417@gmail.com last updated on 09/Feb/19 tg1xx21=a$${sin}^{\mathrm{2}} {a}=\frac{\mathrm{1}}{\mathrm{1}+{cot}^{\mathrm{2}} {a}}=\frac{\mathrm{1}}{\mathrm{1}+{x}^{\mathrm{2}} +{x}^{−\mathrm{2}} −\mathrm{2}}=\frac{{x}^{\mathrm{2}}…