Question Number 51733 by Tinkutara last updated on 30/Dec/18 Commented by maxmathsup by imad last updated on 30/Dec/18 $${let}\:{I}\:=\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} \:\:\:\:\:\frac{{dx}}{{a}^{\mathrm{2}} {cos}^{\mathrm{2}} {x}\:+{b}^{\mathrm{2}} {sin}^{\mathrm{2}} {x}}\:\Rightarrow{I}\:=\int_{\mathrm{0}}…
Question Number 117253 by mathmax by abdo last updated on 10/Oct/20 $$\mathrm{calculate}\:\int_{−\infty} ^{\infty} \:\:\frac{\mathrm{x}^{\mathrm{2}} }{\left(\mathrm{x}^{\mathrm{2}} −\mathrm{x}\:+\mathrm{1}\right)^{\mathrm{2}} }\mathrm{dx} \\ $$ Answered by mnjuly1970 last updated on…
Question Number 117249 by mathmax by abdo last updated on 10/Oct/20 $$\mathrm{calculate}\:\int_{\mathrm{0}} ^{\infty} \:\:\frac{\left(−\mathrm{1}\right)^{\mathrm{x}^{\mathrm{2}} } }{\mathrm{x}^{\mathrm{4}} \:+\mathrm{x}^{\mathrm{2}} \:+\mathrm{1}}\mathrm{dx}\: \\ $$ Answered by mathmax by abdo…
Question Number 182769 by cortano1 last updated on 14/Dec/22 $$\:\:\:\underset{\mathrm{0}} {\overset{\pi/\mathrm{4}} {\int}}\:\frac{{dx}}{\mathrm{sin}\:\left({x}−\mathrm{1}\right)−\mathrm{1}}\:=?\: \\ $$ Answered by ARUNG_Brandon_MBU last updated on 14/Dec/22 $${I}=\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{4}}} \frac{{dx}}{\mathrm{sin}\left({x}−\mathrm{1}\right)−\mathrm{1}}=\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{4}}}…
Question Number 117227 by Eric002 last updated on 10/Oct/20 $${why}\:{every}\:{function}\:{that}\:{is}\:{Riemann} \\ $$$${integrable}\:{is}\:{not}\:{lebsgue}\:{integrable}? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 117221 by bemath last updated on 10/Oct/20 $$\underset{−\infty} {\overset{\:\:\:\:\:\infty} {\int}}\:\frac{\mathrm{cos}\:\left(\mathrm{3}{x}\right)}{{x}^{\mathrm{2}} +\mathrm{4}}\:{dx}\:=? \\ $$ Commented by bemath last updated on 10/Oct/20 $${thank}\:{you}\:{sirs} \\ $$…
Question Number 51680 by Tawa1 last updated on 29/Dec/18 $$\mathrm{Solve}\:\mathrm{the}\:\mathrm{equation}:\:\:\:\:\: \\ $$$$\:\left(\mathrm{1}\right)\:\:\:\:\:\mathrm{z}^{\mathrm{3}} \:+\:\mathrm{1}\:−\:\mathrm{10i}\:\:=\:\:\mathrm{0} \\ $$$$\:\left(\mathrm{2}\right)\:\:\:\:\:\mathrm{z}^{\mathrm{4}} \:−\:\mathrm{i}\:+\:\mathrm{2}\:\:=\:\:\mathrm{0} \\ $$ Commented by maxmathsup by imad last updated…
Question Number 117213 by bobhans last updated on 10/Oct/20 $$\:\:\underset{\mathrm{0}} {\overset{\:\:\:\:\:\:\:\infty} {\int}}\:\frac{\mathrm{tan}^{−\mathrm{1}} \left(\frac{\mathrm{x}}{\mathrm{4}}\right)−\mathrm{tan}^{−\mathrm{1}} \left(\frac{\mathrm{x}}{\mathrm{6}}\right)}{\mathrm{x}}\:\mathrm{dx}\:=? \\ $$ Answered by TANMAY PANACEA last updated on 10/Oct/20 $${taking}\:{help}\:{from}\:{books}…
Question Number 117176 by bemath last updated on 10/Oct/20 $$\underset{\pi/\mathrm{4}} {\overset{\pi/\mathrm{2}} {\int}}\:\frac{\mathrm{4cot}\:{x}+\mathrm{1}\:}{\mathrm{4}−\mathrm{cot}\:{x}}\:{dx}\:=? \\ $$ Commented by bemath last updated on 10/Oct/20 $${the}\:{other}\:{way}\: \\ $$$$\frac{\mathrm{4cot}\:{x}+\mathrm{1}}{\mathrm{4}−\mathrm{cot}\:{x}}\:=\:\mathrm{cot}\:\left({x}−\mathrm{cot}^{−\mathrm{1}} \left(\mathrm{4}\right)\right)…
Question Number 117163 by bemath last updated on 10/Oct/20 $$\:\:\:\int\:\frac{\mathrm{4}\:\mathrm{dx}}{\mathrm{x}\:\sqrt{\mathrm{x}^{\mathrm{2}} −\mathrm{1}}}\:=? \\ $$ Answered by bemath last updated on 10/Oct/20 $$\mathrm{letting}\:\mathrm{x}\:=\:\mathrm{sec}\:\lambda\:\Rightarrow\mathrm{dx}\:=\:\mathrm{sec}\:\lambda\:\mathrm{tan}\:\lambda\:\mathrm{d}\lambda \\ $$$$\mathrm{I}=\:\int\:\frac{\mathrm{4}\:\mathrm{sec}\:\lambda\:\mathrm{tan}\:\lambda}{\mathrm{sec}\:\lambda\:\sqrt{\mathrm{sec}\:^{\mathrm{2}} \lambda−\mathrm{1}}}\:\mathrm{d}\lambda \\…