Question Number 117227 by Eric002 last updated on 10/Oct/20 $${why}\:{every}\:{function}\:{that}\:{is}\:{Riemann} \\ $$$${integrable}\:{is}\:{not}\:{lebsgue}\:{integrable}? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 117221 by bemath last updated on 10/Oct/20 $$\underset{−\infty} {\overset{\:\:\:\:\:\infty} {\int}}\:\frac{\mathrm{cos}\:\left(\mathrm{3}{x}\right)}{{x}^{\mathrm{2}} +\mathrm{4}}\:{dx}\:=? \\ $$ Commented by bemath last updated on 10/Oct/20 $${thank}\:{you}\:{sirs} \\ $$…
Question Number 51680 by Tawa1 last updated on 29/Dec/18 $$\mathrm{Solve}\:\mathrm{the}\:\mathrm{equation}:\:\:\:\:\: \\ $$$$\:\left(\mathrm{1}\right)\:\:\:\:\:\mathrm{z}^{\mathrm{3}} \:+\:\mathrm{1}\:−\:\mathrm{10i}\:\:=\:\:\mathrm{0} \\ $$$$\:\left(\mathrm{2}\right)\:\:\:\:\:\mathrm{z}^{\mathrm{4}} \:−\:\mathrm{i}\:+\:\mathrm{2}\:\:=\:\:\mathrm{0} \\ $$ Commented by maxmathsup by imad last updated…
Question Number 117213 by bobhans last updated on 10/Oct/20 $$\:\:\underset{\mathrm{0}} {\overset{\:\:\:\:\:\:\:\infty} {\int}}\:\frac{\mathrm{tan}^{−\mathrm{1}} \left(\frac{\mathrm{x}}{\mathrm{4}}\right)−\mathrm{tan}^{−\mathrm{1}} \left(\frac{\mathrm{x}}{\mathrm{6}}\right)}{\mathrm{x}}\:\mathrm{dx}\:=? \\ $$ Answered by TANMAY PANACEA last updated on 10/Oct/20 $${taking}\:{help}\:{from}\:{books}…
Question Number 117176 by bemath last updated on 10/Oct/20 $$\underset{\pi/\mathrm{4}} {\overset{\pi/\mathrm{2}} {\int}}\:\frac{\mathrm{4cot}\:{x}+\mathrm{1}\:}{\mathrm{4}−\mathrm{cot}\:{x}}\:{dx}\:=? \\ $$ Commented by bemath last updated on 10/Oct/20 $${the}\:{other}\:{way}\: \\ $$$$\frac{\mathrm{4cot}\:{x}+\mathrm{1}}{\mathrm{4}−\mathrm{cot}\:{x}}\:=\:\mathrm{cot}\:\left({x}−\mathrm{cot}^{−\mathrm{1}} \left(\mathrm{4}\right)\right)…
Question Number 117163 by bemath last updated on 10/Oct/20 $$\:\:\:\int\:\frac{\mathrm{4}\:\mathrm{dx}}{\mathrm{x}\:\sqrt{\mathrm{x}^{\mathrm{2}} −\mathrm{1}}}\:=? \\ $$ Answered by bemath last updated on 10/Oct/20 $$\mathrm{letting}\:\mathrm{x}\:=\:\mathrm{sec}\:\lambda\:\Rightarrow\mathrm{dx}\:=\:\mathrm{sec}\:\lambda\:\mathrm{tan}\:\lambda\:\mathrm{d}\lambda \\ $$$$\mathrm{I}=\:\int\:\frac{\mathrm{4}\:\mathrm{sec}\:\lambda\:\mathrm{tan}\:\lambda}{\mathrm{sec}\:\lambda\:\sqrt{\mathrm{sec}\:^{\mathrm{2}} \lambda−\mathrm{1}}}\:\mathrm{d}\lambda \\…
Question Number 117148 by bemath last updated on 10/Oct/20 $$\:\:\:\int\:\mathrm{x}^{\mathrm{6}} \:\mathrm{e}^{−\mathrm{4x}^{\mathrm{2}} } \:\mathrm{dx}\:=? \\ $$ Answered by Olaf last updated on 10/Oct/20 $$ \\ $$$$\mathrm{I}\:=\:\int\left(−\frac{\mathrm{1}}{\mathrm{8}}{x}^{\mathrm{5}}…
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Question Number 117121 by mnjuly1970 last updated on 09/Oct/20 $$\:\:\:\:\:\:\:\:…{nice}\:\:{mathematics}.. \\ $$$$ \\ $$$$\:\:{please}\:\:{evaluate}… \\ $$$$\: \\ $$$$\:\Omega\:=\int_{−\infty} ^{\:+\infty} \left(\frac{{x}^{\mathrm{2}} −\mathrm{4}}{{x}^{\mathrm{2}} +\mathrm{4}}\ast\:\frac{{sin}\left(\mathrm{2}{x}\right)}{{x}}\right)\:{dx}\:=???\:\: \\ $$$$\:{m}.{n}.\mathrm{1970} \\…
Question Number 182648 by cortano1 last updated on 12/Dec/22 $$\:\:\underset{\mathrm{0}} {\overset{\pi/\mathrm{4}} {\int}}\:\frac{\mathrm{sec}\:^{\mathrm{2}} \mathrm{x}}{\mathrm{tan}\:\mathrm{x}−\mathrm{sec}\:\mathrm{x}}\:\mathrm{dx}\:=? \\ $$ Answered by Acem last updated on 12/Dec/22 $$\:\mathrm{tan}\:{x}\:−\:\mathrm{sec}\:{x}=\:{t}\:\:…..\:{m} \\ $$$$\:\mathrm{sec}\:{x}\:\left(\mathrm{sec}\:{x}−\:\mathrm{tan}\:{x}\right)\:{dx}=\:{dt}…