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Category: Integration

x-2-x-4-dx-

Question Number 117053 by bemath last updated on 09/Oct/20 $$\:\:\:\int\:\frac{\mathrm{x}}{\:\sqrt{\mathrm{2}−\mathrm{x}^{\mathrm{4}} }}\:\mathrm{dx}\:=? \\ $$ Answered by Lordose last updated on 09/Oct/20 $$\mathrm{u}=\mathrm{x}^{\mathrm{2}} \:\Rightarrow\:\mathrm{du}=\mathrm{2xdx} \\ $$$$\mathrm{I}=\frac{\mathrm{1}}{\mathrm{2}}\int\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}−\mathrm{u}^{\mathrm{2}} }}\mathrm{du}…

Question-51510

Question Number 51510 by Tinkutara last updated on 27/Dec/18 Answered by tanmay.chaudhury50@gmail.com last updated on 28/Dec/18 $$\int\frac{−\mathrm{2}{pdp}}{\:\sqrt{{p}^{\mathrm{2}} ×\left(\left\{\mathrm{1}−\mathrm{3}\left({p}^{\mathrm{2}} −\mathrm{1}\right)\right\}\right.}} \\ $$$${x}^{\mathrm{2}} \left\{{x}^{\mathrm{2}} +\frac{\mathrm{1}}{{x}^{\mathrm{2}} }+\mathrm{2}\left({x}+\frac{\mathrm{1}}{{x}}\right)−\mathrm{1}\right\} \\…

Question-51501

Question Number 51501 by Tinkutara last updated on 27/Dec/18 Answered by tanmay.chaudhury50@gmail.com last updated on 27/Dec/18 $${x}={tan}\theta\:\:{dx}={sec}^{\mathrm{2}} \theta{d}\theta \\ $$$$\int\frac{\theta}{{tan}^{\mathrm{4}} \theta}{sec}^{\mathrm{2}} \theta{d}\theta \\ $$$$\theta\int\frac{{sec}^{\mathrm{2}} \theta}{{tan}^{\mathrm{4}}…

dx-1-x-3-1-3-

Question Number 117034 by Lordose last updated on 09/Oct/20 $$\int\frac{\boldsymbol{\mathrm{dx}}}{\:\sqrt[{\mathrm{3}}]{\mathrm{1}+\boldsymbol{\mathrm{x}}^{\mathrm{3}} }} \\ $$ Answered by MJS_new last updated on 09/Oct/20 $$\int\frac{{dx}}{\:\sqrt[{\mathrm{3}}]{{x}^{\mathrm{3}} +\mathrm{1}}}= \\ $$$$\:\:\:\:\:\left[{t}=\frac{\sqrt[{\mathrm{3}}]{{x}^{\mathrm{3}} +\mathrm{1}}}{{x}}\:\rightarrow\:{dx}=−{x}^{\mathrm{2}}…

dx-a-bcosx-2-

Question Number 116999 by TANMAY PANACEA last updated on 08/Oct/20 $$\int\frac{{dx}}{\left({a}+{bcosx}\right)^{\mathrm{2}} } \\ $$ Answered by Olaf last updated on 08/Oct/20 $$\mathrm{I}\left({x}\right)\:=\:\int\frac{{dx}}{\left({a}+{b}\frac{{e}^{{ix}} +{e}^{−{ix}} }{\mathrm{2}}\right)^{\mathrm{2}} }…