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Category: Integration

Question-117511

Question Number 117511 by Canovas last updated on 12/Oct/20 Answered by bemath last updated on 12/Oct/20 dxcos2x(49tan2x)=sec2x49tan2xdx$$=\:\int\:\frac{\mathrm{d}\left(\mathrm{tan}\:\mathrm{x}\right)}{\mathrm{4}−\mathrm{9tan}\:^{\mathrm{2}} \mathrm{x}}\:=\:\int\:\frac{\mathrm{d}\varphi}{\mathrm{4}−\mathrm{9}\varphi^{\mathrm{2}} }…