Category: Integration

Question Number 115661 by bemath last updated on 27/Sep/20 $$\left(\mathrm{1}\right)\:\int\:\mathrm{sin}\:\left(\sqrt{{x}}\right)\:{dx} \\ $$$$\left(\mathrm{2}\right)\:\int\:\mathrm{cos}\:\left(\sqrt{{x}}\:\right)\:{dx}\: \\ $$$$\left(\mathrm{3}\right)\:\int\:\mathrm{tan}\:\left(\sqrt{{x}}\:\right)\:{dx}\: \\ $$ Answered by Dwaipayan Shikari last updated on 27/Sep/20 $$\int\mathrm{sin}\left(\sqrt{\mathrm{x}}\right)\mathrm{dx}\:\:\:\:\:\:\:\:\:\mathrm{x}=\mathrm{t}^{\mathrm{2}}…

Question Number 115594 by MJS_new last updated on 26/Sep/20 $$\mathrm{old}\:\mathrm{question},\:\mathrm{I}\:\mathrm{couldn}'\mathrm{t}\:\mathrm{find}\:\mathrm{it}: \\ $$$$\int\sqrt{{x}−\sqrt{{x}}}{dx}=? \\ $$ Answered by MJS_new last updated on 26/Sep/20 $$\int\sqrt{{x}−\sqrt{{x}}}{dx}= \\ $$$$\:\:\:\:\:\left[{t}=\sqrt{{x}}\:\rightarrow\:{dx}=\mathrm{2}\sqrt{{x}}{dt}\right] \\…

Question Number 50052 by cesar.marval.larez@gmail.com last updated on 13/Dec/18 Commented by maxmathsup by imad last updated on 13/Dec/18 $${let}\:{I}\:=\:\int\:\:\:\frac{{x}^{\mathrm{2}\:} +\mathrm{2}{x}}{\left({x}+\mathrm{1}\right)^{\mathrm{2}} }{dx}\:{changement}\:{x}+\mathrm{1}\:={t}\:{give} \\ $$$${I}\:=\:\int\:\:\frac{\left({t}−\mathrm{1}\right)^{\mathrm{2}} \:+\mathrm{2}\left({t}−\mathrm{1}\right)}{{t}^{\mathrm{2}} }{dt}\:=\int\:\frac{{t}^{\mathrm{2}}…

Question Number 50007 by Joel578 last updated on 13/Dec/18 $$\mathrm{For}\:{a}\:<\:{x}\:<\:{b},\:\mathrm{find}\: \\ $$$$\underset{{a}} {\overset{{b}} {\int}}\:\sqrt{{x}−{a}}\:.\:\sqrt{{b}−{x}}\:{dx} \\ $$ Commented by Abdo msup. last updated on 13/Dec/18 $${changement}\:\sqrt{{x}−{a}}={t}\:{give}\:{x}−{a}={t}^{\mathrm{2}}…

Question Number 115533 by mnjuly1970 last updated on 26/Sep/20 Terms of Service Privacy Policy Contact: info@tinkutara.com