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Category: Integration

matematical-analysis-prove-that-a-gt-0-i-0-sin-2-ax-x-3-2-dx-pia-ii-0-sin-3-

Question Number 115507 by mnjuly1970 last updated on 26/Sep/20 $$\:\:\:\:\:\:\:\:\:\:\:….\:\:\:…{matematical}\:{analysis}…\:\:\: \\ $$$$ \\ $$$$\:\:\:\:\:\:{prove}\:{that}\:::: \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{a}>\mathrm{0}\:::\:\:\:\begin{bmatrix}{{i}\::\:\:\int_{\mathrm{0}\:} ^{\:\infty} \frac{{sin}^{\mathrm{2}} \left({ax}\right)}{{x}^{\frac{\mathrm{3}}{\mathrm{2}}} }\:{dx}=\:\sqrt{\pi{a}}}\\{{ii}:\:\:\:\int_{\mathrm{0}} ^{\:\infty} \frac{{sin}^{\mathrm{3}} \left({ax}\right)}{\:\sqrt{{x}}}\:{dx}\:=\:\frac{−\mathrm{1}+\mathrm{3}\sqrt{\mathrm{3}\:}}{\mathrm{4}}\:\sqrt{\frac{\pi}{\mathrm{6}{a}}\:\:}\:}\end{bmatrix} \\ $$$$\:\:\:\:\:…

find-f-0-1-arctan-x-1-2-x-2-dx-2-calculate-0-1-arctan-2x-1-4x-2-dx-and-0-1-arctan-3x-1-9x-2-dx-

Question Number 49954 by maxmathsup by imad last updated on 12/Dec/18 $${find}\:\:\:{f}\left(\alpha\right)\:=\int_{\mathrm{0}} ^{\mathrm{1}} \:\:\frac{{arctan}\left(\alpha{x}\right)}{\mathrm{1}+\alpha^{\mathrm{2}} {x}^{\mathrm{2}} }{dx} \\ $$$$\left.\mathrm{2}\right)\:{calculate}\:\int_{\mathrm{0}} ^{\mathrm{1}} \:\:\frac{{arctan}\left(\mathrm{2}{x}\right)}{\mathrm{1}+\mathrm{4}{x}^{\mathrm{2}} }\:\:{dx}\:\:{and}\:\int_{\mathrm{0}} ^{\mathrm{1}} \:\:\frac{{arctan}\left(\mathrm{3}{x}\right)}{\mathrm{1}+\mathrm{9}{x}^{\mathrm{2}} }\:{dx}\:. \\…

1-calculate-0-1-ln-1-ix-dx-and-0-1-ln-1-ix-dx-2-find-the-value-of-0-1-ln-1-x-2-dx-

Question Number 49953 by maxmathsup by imad last updated on 12/Dec/18 $$\left.\mathrm{1}\right)\:{calculate}\:\int_{\mathrm{0}} ^{\mathrm{1}} {ln}\left(\mathrm{1}+{ix}\right){dx}\:{and}\:\int_{\mathrm{0}} ^{\mathrm{1}} {ln}\left(\mathrm{1}−{ix}\right){dx} \\ $$$$\left.\mathrm{2}\right)\:{find}\:{the}\:{value}\:{of}\:\int_{\mathrm{0}} ^{\mathrm{1}} {ln}\left(\mathrm{1}+{x}^{\mathrm{2}} \right){dx}\:. \\ $$ Commented by…

Question-49950

Question Number 49950 by ajfour last updated on 12/Dec/18 Commented by ajfour last updated on 12/Dec/18 $$\:\:{y}\:=\:\mid\frac{{b}}{\mathrm{2}}+{b}\mathrm{sin}\:\theta\mid\:\:,\:{x}\:=\:{a}\mathrm{cos}\:\theta \\ $$$${Find}\:{area}\:{enclosed}\:{by}\:{the}\:{curve}. \\ $$ Answered by MJS last…