Category: Integration

Question Number 117089 by mnjuly1970 last updated on 09/Oct/20 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 51552 by maxmathsup by imad last updated on 28/Dec/18 $$calculate{\int }_0^{+\mathrm{\infty }}\frac{arctan(1+x^2)}{x^2+4}dx$$ Commented by Abdo msup. last updated on…

Question Number 117087 by mnjuly1970 last updated on 09/Oct/20 $$\dots nicecalculus\dots$$$$pleaseevaluate::$$$$$$$$\mathrm{\Omega }={\int }_0^1\frac{x^4+1}{x^6+1}dx=???$$$$m.n.1970$$ Answered…

Question Number 117066 by bemath last updated on 09/Oct/20 $$\mathrm{Given}\mathrm{f}\left(\mathrm{x}\right)=\frac{\mathrm{x}-1}{\mathrm{x}+1}.\mathrm{If}{\mathrm{f}}^2\left(\mathrm{x}\right)=\mathrm{f}\left(\mathrm{f}\left(\mathrm{x}\right)\right),$$$${\mathrm{f}}^3\left(\mathrm{x}\right)=\mathrm{f}\left(\mathrm{f}\left(\mathrm{f}\left(\mathrm{x}\right)\right)\right),{\mathrm{f}}^{1998}\left(\mathrm{x}\right)=\mathrm{g}\left(\mathrm{x}\right)$$$$\mathrm{then}{\int }_{\frac{1}{\mathrm{e}}}^1\mathrm{g}\left(\mathrm{x}\right)\mathrm{dx}=\mathrm{\_}?$$ Answered by 1549442205PVT last…

Question Number 117053 by bemath last updated on 09/Oct/20 $$\int \frac{\mathrm{x}}{\sqrt{2-{\mathrm{x}}^4}}\mathrm{dx}=?$$ Answered by Lordose last updated on 09/Oct/20 $$\mathrm{u}={\mathrm{x}}^2\Rightarrow \mathrm{du}=2\mathrm{xdx}$$$$\mathrm{I}=\frac{\mathrm{1}}{\mathrm{2}}\int\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}−\mathrm{u}^{\mathrm{2}} }}\mathrm{du}…