Menu Close

Category: Integration

find-sin-pix-3-cos-2pix-dx-

Question Number 48178 by Abdo msup. last updated on 20/Nov/18 $${find}\:\:\int\:\:\:\frac{{sin}\left(\pi{x}\right)}{\mathrm{3}\:+{cos}\left(\mathrm{2}\pi{x}\right)}{dx} \\ $$ Commented by Abdo msup. last updated on 25/Nov/18 $${A}=\int\:\:\:\frac{{sin}\left(\pi{x}\right)}{\mathrm{3}+{cos}\left(\mathrm{2}\pi{x}\right)}{dx}\:=_{\pi{x}\:={t}} \:\:\frac{\mathrm{1}}{\pi}\int\:\:\:\frac{{sin}\left({t}\right)}{\mathrm{3}+{cos}\left(\mathrm{2}{t}\right)}{dt} \\ $$$$\:\int\:\:\:\frac{{sin}\left({t}\right)}{\mathrm{3}\:+\mathrm{2}{cos}^{\mathrm{2}}…

calculate-arctan-x-1-x-2-dx-

Question Number 48173 by Abdo msup. last updated on 20/Nov/18 $${calculate}\:\int\:\:\frac{{arctan}\left({x}\right)}{\:\sqrt{\mathrm{1}+{x}^{\mathrm{2}} }}{dx} \\ $$ Commented by maxmathsup by imad last updated on 26/Nov/18 $${changement}\:{x}={tant}\:{give}\:\:{I}\:=\:\int\:\frac{{t}}{\:\sqrt{\mathrm{1}+{tan}^{\mathrm{2}} {t}}}\:\left(\mathrm{1}+{tan}^{\mathrm{2}}…

Question-113675

Question Number 113675 by AbhishekBasnet last updated on 14/Sep/20 Commented by mohammad17 last updated on 14/Sep/20 $$\left.=−\:\frac{\mathrm{1}}{{b}}\int\left(\left({a}−{bx}\right)−{a}\right)\left({a}−{bx}\right)^{−\frac{\mathrm{1}}{\mathrm{2}}} \right){dx} \\ $$$$ \\ $$$$=−\frac{\mathrm{1}}{{b}}\int\left(\left({a}−{bx}\right)^{\frac{\mathrm{1}}{\mathrm{2}}} −{a}\left({a}−{bx}\right)^{−\frac{\mathrm{1}}{\mathrm{2}}} \right){dx} \\…

Question-48127

Question Number 48127 by cesar.marval.larez@gmail.com last updated on 19/Nov/18 Answered by tanmay.chaudhury50@gmail.com last updated on 19/Nov/18 $$\left.\mathrm{30}\right){t}=\frac{−\mathrm{1}}{{x}}\:\:\:{dt}=\frac{\mathrm{1}}{{x}^{\mathrm{2}} }{dx} \\ $$$$\int{e}^{{t}} {dt}={e}^{{t}} +{c} \\ $$$${e}^{{t}} +{c}…

1-tan-3x-2-2-1-sin-3x-dx-

Question Number 113656 by bobhans last updated on 14/Sep/20 $$\:\:\int\:\frac{\left(\mathrm{1}+\mathrm{tan}\:\left(\frac{\mathrm{3x}}{\mathrm{2}}\right)\right)^{\mathrm{2}} }{\mathrm{1}+\mathrm{sin}\:\mathrm{3x}}\:\mathrm{dx}\:? \\ $$ Answered by john santu last updated on 14/Sep/20 $$\:{setting}\:\mathrm{tan}\:\left(\frac{\mathrm{3}{x}}{\mathrm{2}}\right)\:=\:{s}\:\rightarrow\mathrm{sin}\:\mathrm{3}{x}\:=\:\frac{\mathrm{2}{s}}{\mathrm{1}+{s}^{\mathrm{2}} } \\ $$$$\mathrm{1}+\mathrm{sin}\:\mathrm{3}{x}\:=\:\frac{\left(\mathrm{1}+{s}\right)^{\mathrm{2}}…