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Category: Integration

dx-3sin-x-sin-3-x-

Question Number 113275 by bemath last updated on 12/Sep/20 $$\:\int\:\frac{\mathrm{dx}}{\mathrm{3sin}\:\mathrm{x}+\mathrm{sin}\:^{\mathrm{3}} \mathrm{x}}\:? \\ $$ Answered by bemath last updated on 12/Sep/20 $$\mathrm{I}\:=\:\int\:\frac{\mathrm{dx}}{\mathrm{sin}\:\mathrm{x}\left(\mathrm{3}+\mathrm{sin}\:^{\mathrm{2}} \mathrm{x}\right)} \\ $$$$\mathrm{I}=\int\:\frac{\mathrm{sin}\:\mathrm{x}\:\mathrm{dx}}{\mathrm{sin}\:^{\mathrm{2}} \mathrm{x}\left(\mathrm{3}+\mathrm{sin}\:^{\mathrm{2}}…

A-particle-of-mass-4kg-was-at-rest-a-a-point-of-position-vector-i-4j-A-force-F-was-applied-to-it-and-it-moved-at-a-velocity-of-3i-7j-ms-1-after-a-time-of-5seconds-Find-a-the-magnitude-o

Question Number 47675 by Rio Michael last updated on 13/Nov/18 $${A}\:{particle}\:{of}\:{mass}\:\mathrm{4}{kg}\:{was}\:{at}\:{rest}\:{a}\:{a}\:{point}\:{of}\:{position}\:{vector} \\ $$$${i}\:+\mathrm{4}{j}.\:{A}\:{force}\:{F}\:{was}\:{applied}\:{to}\:{it}\:{and}\:{it}\:{moved}\:{at}\:{a}\:{velocity} \\ $$$${of}\:\left(\mathrm{3}{i}\:+\:\mathrm{7}{j}\right){ms}^{−\mathrm{1}} \:\:\:{after}\:{a}\:{time}\:{of}\:\:\mathrm{5}{seconds}.\:{Find}\: \\ $$$$\left.{a}\right)\:{the}\:{magnitude}\:{of}\:{F} \\ $$$$\left.{b}\right)\:{The}\:{speed}\:{at}\:{which}\:{it}\:{moves},{Hence}, \\ $$$$\left.{c}\right)\:{The}\:{distance}\:{it}\:{covered}. \\ $$$$ \\…

calculate-0-dx-x-4-2x-2-3-

Question Number 113203 by abdomsup last updated on 11/Sep/20 $${calculate}\:\int_{\mathrm{0}} ^{\infty} \:\:\:\frac{{dx}}{{x}^{\mathrm{4}} \:+\mathrm{2}{x}^{\mathrm{2}} +\mathrm{3}} \\ $$ Answered by 1549442205PVT last updated on 11/Sep/20 $$\mathrm{Consider}\:\mathrm{f}\left(\mathrm{z}\right)=\frac{\mathrm{1}}{\mathrm{z}^{\mathrm{4}} +\mathrm{2z}^{\mathrm{2}}…

calculus-Evaluate-I-0-1-1-x-x-1-x-2-x-3-1-3x-dx-M-N-july-1970-

Question Number 113198 by mnjuly1970 last updated on 11/Sep/20 $$\:\:\:\:\:\:\:\:\:….\:{calculus}…. \\ $$$$\:\:\:\:\:\:\mathscr{E}{valuate}\:::: \\ $$$$ \\ $$$$\:\:\:\:\:\:\:\:\mathrm{I}\::=\int_{\mathrm{0}} ^{\:\mathrm{1}} \frac{\mathrm{1}}{\:\sqrt{{x}\left({x}+\mathrm{1}\right)\left({x}+\mathrm{2}\right)\left({x}+\mathrm{3}\right)+\mathrm{1}}−\mathrm{3}{x}}{dx}=??? \\ $$$$ \\ $$$$\:\:\:\:\:\:\:\:\mathscr{M}.\mathscr{N}.{july}\:\mathrm{1970}# \\ $$$$\:\: \\…

Question-178712

Question Number 178712 by mnjuly1970 last updated on 20/Oct/22 Answered by mr W last updated on 20/Oct/22 $$\frac{\mathrm{1}}{{n}}\left(\frac{\mathrm{1}}{\mathrm{4}{n}^{\mathrm{2}} −\mathrm{1}}\right)=\frac{\mathrm{1}}{\mathrm{2}{n}}\left(\frac{\mathrm{1}}{\mathrm{2}{n}−\mathrm{1}}−\frac{\mathrm{1}}{\mathrm{2}{n}+\mathrm{1}}\right) \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\frac{\mathrm{1}}{\mathrm{2}{n}−\mathrm{1}}+\frac{\mathrm{1}}{\mathrm{2}{n}+\mathrm{1}}−\frac{\mathrm{1}}{{n}} \\ $$$$ \\ $$$$\underset{{n}=\mathrm{1}}…