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Question Number 114566 by Akeyz last updated on 19/Sep/20 Answered by mathmax by abdo last updated on 19/Sep/20 $$\mathrm{we}\:\mathrm{have}\:\prod_{\mathrm{k}=\mathrm{1}} ^{\infty} \:\mathrm{cos}\left(\frac{\mathrm{x}}{\mathrm{2}^{\mathrm{k}} }\right)\:=\mathrm{lim}_{\mathrm{n}\rightarrow+\infty} \mathrm{A}_{\mathrm{n}} \left(\mathrm{x}\right)\:\mathrm{with}\:\mathrm{A}_{\mathrm{n}} \left(\mathrm{x}\right)=\prod_{\mathrm{k}=\mathrm{1}}…
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