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Category: Integration

let-f-x-0-x-t-sin-t-dt-1-find-a-explicit-form-of-f-x-2-calculate-0-pi-2-t-sint-dt-

Question Number 46843 by maxmathsup by imad last updated on 01/Nov/18 $${let}\:{f}\left({x}\right)=\:\int_{\mathrm{0}} ^{{x}} \:\frac{{t}}{{sin}\left({t}\right)}{dt} \\ $$$$\left.\mathrm{1}\right)\:{find}\:{a}\:{explicit}\:{form}\:{of}\:{f}\left({x}\right) \\ $$$$\left.\mathrm{2}\right)\:{calculate}\:\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} \:\frac{{t}}{{sint}}{dt} \\ $$ Terms of Service…

find-sin2x-dx-

Question Number 46837 by  last updated on 01/Nov/18 $${find}\int\sqrt{{sin}\mathrm{2}{x}}\:{dx}=?? \\ $$ Commented by maxmathsup by imad last updated on 03/Nov/18 $${not}\:{solvable}\:{by}\:{elementary}\:{function}\:{but}\:{we}\:{can}\:{find}\:{approxmation}\:{if}\:{we}\: \\ $$$${have}\:{the}\:{limits}… \\…

Question-46838

Question Number 46838 by peter frank last updated on 01/Nov/18 Answered by MrW3 last updated on 03/Nov/18 $$\frac{{x}^{\mathrm{2}} }{{a}^{\mathrm{2}} }+\frac{{y}^{\mathrm{2}} }{{b}^{\mathrm{2}} }=\mathrm{1} \\ $$$$\frac{\mathrm{2}{x}}{{a}^{\mathrm{2}} }+\frac{\mathrm{2}{y}}{{b}^{\mathrm{2}}…

0-1-sin-x-cos-2-x-cos-2-pi-5-cos-2-x-cos-2-2pi-5-sin-5x-dx-

Question Number 177906 by cortano1 last updated on 11/Oct/22 $$\:\:\underset{\mathrm{0}} {\overset{\mathrm{1}} {\int}}\:\frac{\mathrm{sin}\:\mathrm{x}\left(\mathrm{cos}\:^{\mathrm{2}} \mathrm{x}−\mathrm{cos}\:^{\mathrm{2}} \frac{\pi}{\mathrm{5}}\right)\left(\mathrm{cos}\:^{\mathrm{2}} \mathrm{x}−\mathrm{cos}\:^{\mathrm{2}} \frac{\mathrm{2}\pi}{\mathrm{5}}\right)}{\mathrm{sin}\:\mathrm{5x}}\:\mathrm{dx}\:=? \\ $$ Answered by Frix last updated on 11/Oct/22…

pi-2-pi-dx-sin-x-2cos-x-2-

Question Number 177820 by cortano1 last updated on 09/Oct/22 $$\:\:\:\:\underset{\pi/\mathrm{2}} {\overset{\pi} {\int}}\:\frac{\mathrm{dx}}{\left(\mathrm{sin}\:\mathrm{x}−\mathrm{2cos}\:\mathrm{x}\right)^{\mathrm{2}} }\:=? \\ $$ Answered by qaz last updated on 09/Oct/22 $$\int_{\pi/\mathrm{2}} ^{\pi} \frac{{dx}}{\left(\mathrm{sin}\:{x}−\mathrm{2cos}\:{x}\right)^{\mathrm{2}}…