Question Number 46740 by math khazana by abdo last updated on 30/Oct/18 $${find}\:\int\:\:{x}\sqrt{\frac{\mathrm{1}−\sqrt{{x}}}{\mathrm{1}+\sqrt{{x}}}}{dx} \\ $$ Commented by behi83417@gmail.com last updated on 31/Oct/18 $$=\int{x}.\sqrt{\frac{\left(\mathrm{1}−\sqrt{{x}}\right)\left(\mathrm{1}−\sqrt{{x}}\right)}{\left(\mathrm{1}+\sqrt{{x}}\right)\left(\mathrm{1}−\sqrt{{x}}\right)}}{dx}= \\ $$$$=\int{x}.\frac{\mathrm{1}−\sqrt{{x}}}{\:\sqrt{\mathrm{1}−{x}}}{dx}=\int\left[\frac{{x}}{\:\sqrt{\mathrm{1}−{x}}}−\frac{{x}\sqrt{{x}}}{\:\sqrt{\mathrm{1}−{x}}}\right]{dx}=…
Question Number 112271 by bemath last updated on 07/Sep/20 $$\:\:\:\:\sqrt{\mathrm{bemath}} \\ $$$$\:\:\:\int\:\mathrm{sin}\:\mathrm{x}\:\sqrt{\mathrm{1}−\mathrm{sin}\:\mathrm{x}}\:\mathrm{dx}\:? \\ $$ Answered by maths mind last updated on 07/Sep/20 $$\mathrm{1}−{sin}\left({x}\right)=\left({sin}\left(\frac{{x}}{\mathrm{2}}\right)−{cos}\left(\frac{{x}}{\mathrm{2}}\right)\right)^{\mathrm{2}} \\ $$…
Question Number 46720 by Necxx last updated on 30/Oct/18 Commented by Necxx last updated on 30/Oct/18 $${please}\:{help}\:{with}\:{no}.\:\mathrm{15}\:{cos}\:{i}\:{got}\:{it} \\ $$$${as} \\ $$$$−\mathrm{sin}^{−\mathrm{1}} \left(\frac{\mathrm{1}}{{x}}\right)−\:\frac{\sqrt{{x}^{\mathrm{2}} +\mathrm{1}}}{{x}}\:+{c} \\ $$…
Question Number 177784 by mnjuly1970 last updated on 09/Oct/22 Answered by aleks041103 last updated on 09/Oct/22 Commented by aleks041103 last updated on 09/Oct/22 $${construct} \\…
Question Number 112251 by bobhans last updated on 07/Sep/20 $$\int\:\frac{\mathrm{dx}}{\left(\mathrm{x}^{\mathrm{4}} −\mathrm{1}\right)\sqrt{\mathrm{x}^{\mathrm{2}} +\mathrm{1}}} \\ $$ Answered by john santu last updated on 07/Sep/20 $$\int\:\frac{{dx}}{\left({x}^{\mathrm{4}} −\mathrm{1}\right)\sqrt{{x}^{\mathrm{2}} +\mathrm{1}}}\:?…
Question Number 112249 by MJS_new last updated on 07/Sep/20 $$\int\frac{{dx}}{\left(\alpha{x}^{\mathrm{2}} +{px}+\beta\right)\sqrt{\alpha{x}^{\mathrm{2}} +{qx}+\beta}}=? \\ $$ Commented by bemath last updated on 07/Sep/20 $$\mathrm{waw}….. \\ $$ Answered…
Question Number 177775 by depressiveshrek last updated on 08/Oct/22 $$\int\frac{\mathrm{sin2}{x}}{\:\sqrt{\mathrm{cos}^{\mathrm{4}} {x}+\mathrm{1}}}{dx} \\ $$ Answered by Ar Brandon last updated on 08/Oct/22 $${I}=\int\frac{\mathrm{sin2}{x}}{\:\sqrt{\mathrm{cos}^{\mathrm{4}} {x}+\mathrm{1}}}{dx}=\int\frac{\mathrm{2sin}{x}\mathrm{cos}{x}}{\:\sqrt{\mathrm{cos}^{\mathrm{4}} {x}+\mathrm{1}}}{dx}\:,\:{c}=\mathrm{cos}{x} \\…
Question Number 46673 by Tawa1 last updated on 30/Oct/18 Commented by Smail last updated on 30/Oct/18 $$\alpha\:{is}\:{a}\:{constant}\:{you}\:{should}\:{not}\:{replace}\:{it}\:{with}\:{t}\mathrm{2}^{{x}} .\: \\ $$ Commented by Smail last updated…
Question Number 112206 by Eric002 last updated on 06/Sep/20 $$\int{ln}\left({sin}\left({x}\right)\right)\:{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 46667 by Necxx last updated on 29/Oct/18 $${integrate}\:\mathrm{ln}\:\left({cosx}+{sinx}\right){dx} \\ $$ Commented by maxmathsup by imad last updated on 29/Oct/18 $${let}\:{f}\left({x}\right)=\int_{\mathrm{0}} ^{{x}} {ln}\left({cost}\:+{sint}\right){dt}\:\:{we}\:{have} \\…