Question Number 46534 by peter frank last updated on 28/Oct/18 $$\mathrm{using}\:\mathrm{taylors}\:\mathrm{expansion} \\ $$$$\mathrm{find}\:\mathrm{find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of} \\ $$$$\left.\mathrm{a}\right)\mathrm{tan45}°\:\mathrm{1}'\: \\ $$$$\left.\mathrm{b}\right)\mathrm{sin30}°\:\mathrm{1}' \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on…
Question Number 177604 by mnjuly1970 last updated on 07/Oct/22 $$ \\ $$$$\:\:\:\:\:\:\:\:\mathrm{Calculate} \\ $$$$\:\:\:\:\:\boldsymbol{\phi}=\int_{\mathrm{0}} ^{\:\mathrm{1}} \frac{\:\mathrm{ln}\left({x}\:\right)}{\mathrm{1}\:+\:{x}^{\:\mathrm{2}} }\:\mathrm{d}{x}\:\overset{?} {=}\:−\mathrm{G} \\ $$$$\:\:\:\:\sim\:\mathrm{Solution}\:\sim \\ $$$$\:\:\:\:\:\:\boldsymbol{\phi}\:=\:\int_{\mathrm{0}} ^{\:\mathrm{1}} \left\{\underset{{k}=\mathrm{0}} {\overset{\infty}…
Question Number 46522 by Tawa1 last updated on 27/Oct/18 $$\int\:\mathrm{x}\:\mathrm{cot}^{−\mathrm{1}} \left(\mathrm{3x}^{\mathrm{2}} \right)\:\mathrm{tan}^{−\mathrm{1}} \left(\mathrm{6x}^{\mathrm{2}} \right) \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 46499 by Tawa1 last updated on 27/Oct/18 Answered by MJS last updated on 27/Oct/18 $$\int\frac{\mathrm{6sin}\:{x}\:\mathrm{cos}^{\mathrm{2}} \:{x}\:+\mathrm{sin}\:\mathrm{2}{x}\:−\mathrm{23sin}\:{x}}{\left(\mathrm{1}−\mathrm{cos}\:{x}\right)^{\mathrm{2}} \left(\mathrm{5}−\mathrm{sin}^{\mathrm{2}} \:{x}\right)}{dx}= \\ $$$$=\int\frac{\mathrm{6cos}^{\mathrm{2}} \:{x}\:+\mathrm{2cos}\:{x}\:−\mathrm{23}}{\left(\mathrm{1}−\mathrm{cos}\:{x}\right)^{\mathrm{2}} \left(\mathrm{4}+\mathrm{cos}^{\mathrm{2}} \:{x}\right)}\mathrm{sin}\:{x}\:{dx}=…
Question Number 177541 by peter frank last updated on 06/Oct/22 Commented by cortano1 last updated on 07/Oct/22 $$\underset{\mathrm{0}} {\overset{\mathrm{k}} {\int}}\:\frac{\mathrm{8}}{\left(\mathrm{x}+\mathrm{1}\right)\left(\mathrm{x}^{\mathrm{2}} +\mathrm{3}\right)}\:\mathrm{dx}=\mathrm{ln}\:\mathrm{k}+\frac{\pi\sqrt{\mathrm{3}}}{\mathrm{k}^{\mathrm{2}} }\:? \\ $$ Commented…
Question Number 46465 by rahul 19 last updated on 26/Oct/18 $${If}\:{I}=\frac{\mathrm{1}}{\mathrm{2}}\:\int_{\mathrm{0}} ^{\infty} {t}^{{n}} {e}^{−{t}} {dt}\:\:=\:\mathrm{360}. \\ $$$${Find}\:{n}? \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on…
Question Number 46432 by rahul 19 last updated on 26/Oct/18 Commented by rahul 19 last updated on 29/Oct/18 $$?????? \\ $$ Commented by rahul 19…
Question Number 46423 by maxmathsup by imad last updated on 25/Oct/18 $${calculate}\:\int_{\mathrm{0}} ^{\infty} \:\:\frac{{arctan}\left({x}^{\mathrm{2}} \right)}{\mathrm{1}+{x}^{\mathrm{2}} }{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 46418 by maxmathsup by imad last updated on 25/Oct/18 $${find}\:\:\int\int_{\left[\mathrm{0},\mathrm{1}\right]×\left[\mathrm{0},\mathrm{1}\right]} \left(\sqrt{{x}+\sqrt{{y}}}−\sqrt{{y}+\sqrt{{x}}}\right){dxdy} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 46369 by Joel578 last updated on 24/Oct/18 $$\int\:\frac{{dx}}{{x}\sqrt{{x}^{\mathrm{2}} \:+\:\mathrm{2}{x}\:−\:\mathrm{1}}}\:\:=\:\mathrm{tan}^{−\mathrm{1}} \left(\frac{{x}\:−\:\mathrm{1}}{\:\sqrt{{x}^{\mathrm{2}} \:+\:\mathrm{2}{x}\:−\:\mathrm{1}}}\right)\:+\:{C} \\ $$$$ \\ $$$$\mathrm{I}'\mathrm{m}\:\mathrm{confused}\:\mathrm{in}\:\mathrm{choosing}\:\mathrm{the}\:\mathrm{right}\:\mathrm{substitution} \\ $$$$\mathrm{so}\:\mathrm{that}\:\mathrm{we}\:\mathrm{can}\:\mathrm{get}\:\mathrm{the}\:\mathrm{result}\:\mathrm{above}. \\ $$$$\mathrm{Please}\:\mathrm{help}… \\ $$ Commented by…