Question Number 177906 by cortano1 last updated on 11/Oct/22 $$\:\:\underset{\mathrm{0}} {\overset{\mathrm{1}} {\int}}\:\frac{\mathrm{sin}\:\mathrm{x}\left(\mathrm{cos}\:^{\mathrm{2}} \mathrm{x}−\mathrm{cos}\:^{\mathrm{2}} \frac{\pi}{\mathrm{5}}\right)\left(\mathrm{cos}\:^{\mathrm{2}} \mathrm{x}−\mathrm{cos}\:^{\mathrm{2}} \frac{\mathrm{2}\pi}{\mathrm{5}}\right)}{\mathrm{sin}\:\mathrm{5x}}\:\mathrm{dx}\:=? \\ $$ Answered by Frix last updated on 11/Oct/22…
Question Number 46833 by physics last updated on 01/Nov/18 Commented by physics last updated on 01/Nov/18 $${question}\:\mathrm{19}\:{please}\:{solve} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 177820 by cortano1 last updated on 09/Oct/22 $$\:\:\:\:\underset{\pi/\mathrm{2}} {\overset{\pi} {\int}}\:\frac{\mathrm{dx}}{\left(\mathrm{sin}\:\mathrm{x}−\mathrm{2cos}\:\mathrm{x}\right)^{\mathrm{2}} }\:=? \\ $$ Answered by qaz last updated on 09/Oct/22 $$\int_{\pi/\mathrm{2}} ^{\pi} \frac{{dx}}{\left(\mathrm{sin}\:{x}−\mathrm{2cos}\:{x}\right)^{\mathrm{2}}…
Question Number 46748 by last updated on 31/Oct/18 $$\int\sqrt{{sin}\mathrm{2}{x}}\:{dx}=?? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 46740 by math khazana by abdo last updated on 30/Oct/18 $${find}\:\int\:\:{x}\sqrt{\frac{\mathrm{1}−\sqrt{{x}}}{\mathrm{1}+\sqrt{{x}}}}{dx} \\ $$ Commented by behi83417@gmail.com last updated on 31/Oct/18 $$=\int{x}.\sqrt{\frac{\left(\mathrm{1}−\sqrt{{x}}\right)\left(\mathrm{1}−\sqrt{{x}}\right)}{\left(\mathrm{1}+\sqrt{{x}}\right)\left(\mathrm{1}−\sqrt{{x}}\right)}}{dx}= \\ $$$$=\int{x}.\frac{\mathrm{1}−\sqrt{{x}}}{\:\sqrt{\mathrm{1}−{x}}}{dx}=\int\left[\frac{{x}}{\:\sqrt{\mathrm{1}−{x}}}−\frac{{x}\sqrt{{x}}}{\:\sqrt{\mathrm{1}−{x}}}\right]{dx}=…
Question Number 112271 by bemath last updated on 07/Sep/20 $$\:\:\:\:\sqrt{\mathrm{bemath}} \\ $$$$\:\:\:\int\:\mathrm{sin}\:\mathrm{x}\:\sqrt{\mathrm{1}−\mathrm{sin}\:\mathrm{x}}\:\mathrm{dx}\:? \\ $$ Answered by maths mind last updated on 07/Sep/20 $$\mathrm{1}−{sin}\left({x}\right)=\left({sin}\left(\frac{{x}}{\mathrm{2}}\right)−{cos}\left(\frac{{x}}{\mathrm{2}}\right)\right)^{\mathrm{2}} \\ $$…
Question Number 46720 by Necxx last updated on 30/Oct/18 Commented by Necxx last updated on 30/Oct/18 $${please}\:{help}\:{with}\:{no}.\:\mathrm{15}\:{cos}\:{i}\:{got}\:{it} \\ $$$${as} \\ $$$$−\mathrm{sin}^{−\mathrm{1}} \left(\frac{\mathrm{1}}{{x}}\right)−\:\frac{\sqrt{{x}^{\mathrm{2}} +\mathrm{1}}}{{x}}\:+{c} \\ $$…
Question Number 177784 by mnjuly1970 last updated on 09/Oct/22 Answered by aleks041103 last updated on 09/Oct/22 Commented by aleks041103 last updated on 09/Oct/22 $${construct} \\…
Question Number 112251 by bobhans last updated on 07/Sep/20 $$\int\:\frac{\mathrm{dx}}{\left(\mathrm{x}^{\mathrm{4}} −\mathrm{1}\right)\sqrt{\mathrm{x}^{\mathrm{2}} +\mathrm{1}}} \\ $$ Answered by john santu last updated on 07/Sep/20 $$\int\:\frac{{dx}}{\left({x}^{\mathrm{4}} −\mathrm{1}\right)\sqrt{{x}^{\mathrm{2}} +\mathrm{1}}}\:?…
Question Number 112249 by MJS_new last updated on 07/Sep/20 $$\int\frac{{dx}}{\left(\alpha{x}^{\mathrm{2}} +{px}+\beta\right)\sqrt{\alpha{x}^{\mathrm{2}} +{qx}+\beta}}=? \\ $$ Commented by bemath last updated on 07/Sep/20 $$\mathrm{waw}….. \\ $$ Answered…