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Category: Integration

Question-178922

Question Number 178922 by mnjuly1970 last updated on 22/Oct/22 Answered by ARUNG_Brandon_MBU last updated on 22/Oct/22 1n(n+1)(n+2)=12n1n+1+12n+2(1n(n+1)(n+2))2=14(1n2n+1+1n+2)2$$=\frac{\mathrm{1}}{\mathrm{4}}\left(\frac{\mathrm{1}}{{n}^{\mathrm{2}} }+\frac{\mathrm{4}}{\left({n}+\mathrm{1}\right)^{\mathrm{2}} }+\frac{\mathrm{1}}{\left({n}+\mathrm{2}\right)^{\mathrm{2}} }+\mathrm{2}\left(\frac{−\mathrm{2}}{{n}\left({n}+\mathrm{1}\right)}+\frac{−\mathrm{2}}{\left({n}+\mathrm{1}\right)\left({n}+\mathrm{2}\right)}+\frac{\mathrm{1}}{{n}\left({n}+\mathrm{2}\right)}\right)\right)…

Question-178832

Question Number 178832 by Spillover last updated on 22/Oct/22 Answered by ARUNG_Brandon_MBU last updated on 22/Oct/22 a.y(y8)(y4)2dy=((y4)+4)((y4)4)(y4)2dy$$\:\:\:\:=\int\frac{\left(\mathrm{y}−\mathrm{4}\right)^{\mathrm{2}} −\mathrm{16}}{\left(\mathrm{y}−\mathrm{4}\right)^{\mathrm{2}} }{d}\mathrm{y}=\int\left(\mathrm{1}−\frac{\mathrm{16}}{\left(\mathrm{y}−\mathrm{4}\right)^{\mathrm{2}} }\right){d}\mathrm{y} \

A-particle-of-mass-4kg-was-at-rest-a-a-point-of-position-vector-i-4j-A-force-F-was-applied-to-it-and-it-moved-at-a-velocity-of-3i-7j-ms-1-after-a-time-of-5seconds-Find-a-the-magnitude-o

Question Number 47675 by Rio Michael last updated on 13/Nov/18 Aparticleofmass4kgwasatrestaapointofpositionvectori+4j.AforceFwasappliedtoitanditmovedatavelocityof(3i+7j)ms1afteratimeof5seconds.Finda)themagnitudeofFb)Thespeedatwhichitmoves,Hence,c)Thedistanceitcovered.$$ \