Question Number 111025 by mathmax by abdo last updated on 01/Sep/20 $$\mathrm{calculate}\:\int_{\mathrm{0}} ^{\infty} \:\:\frac{\mathrm{x}^{\mathrm{2}} \mathrm{ln}\left(\mathrm{x}\right)}{\left(\mathrm{1}+\mathrm{x}\right)^{\mathrm{4}} }\mathrm{dx} \\ $$ Answered by mathdave last updated on 01/Sep/20…
Question Number 111024 by mathmax by abdo last updated on 01/Sep/20 $$\mathrm{calculate}\:\int_{\mathrm{0}} ^{\infty} \:\frac{\mathrm{x}^{\mathrm{2}} \mathrm{lnx}}{\left(\mathrm{1}+\mathrm{x}^{\mathrm{2}} \right)^{\mathrm{3}} }\mathrm{dx} \\ $$ Answered by mathdave last updated on…
Question Number 45482 by Meritguide1234 last updated on 13/Oct/18 Answered by ajfour last updated on 13/Oct/18 $${f}\left({x}\right)=\frac{\mathrm{1}−\mathrm{2}{x}}{\mathrm{7}}\:\:;\:\:\:\:{f}\left(\mathrm{4}\right)=\:−\mathrm{1}\: \\ $$$$\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_ \\ $$$${let}\:\:\:{f}\left({x}\right)={ax}^{\mathrm{2}} +{bx}+{c}+\mathrm{1} \\ $$$$\int_{\mathrm{0}} ^{\:\:{x}}…
Question Number 111017 by bemath last updated on 01/Sep/20 $$\:\:\:\:\sqrt{\mathrm{bemath}} \\ $$$$\int\:\frac{\mathrm{dx}}{\:\sqrt[{\mathrm{4}\:}]{\mathrm{4}−\sqrt[{\mathrm{3}\:}]{\mathrm{3}−\mathrm{2x}}}}\:? \\ $$ Answered by john santu last updated on 01/Sep/20 $${by}\:{letting}\:\nu\:=\:\sqrt[{\mathrm{4}\:}]{\mathrm{4}−\sqrt[{\mathrm{3}\:}]{\mathrm{3}−\mathrm{2}{x}}} \\ $$$$\Rightarrow\nu^{\mathrm{4}}…
Question Number 111010 by mohammad17 last updated on 01/Sep/20 $$\int{e}^{{x}} \:{tanx}\:{dx} \\ $$ Answered by Rio Michael last updated on 02/Sep/20 $$\mathrm{Let}\:\mathrm{me}\:\mathrm{try}\:\mathrm{this},\:\mathrm{it}'\mathrm{s}\:\:\mathrm{something}\:\mathrm{i}\:\mathrm{learnt} \\ $$$$\mathrm{on}\:\mathrm{my}\:\mathrm{own}. \\…
Question Number 176542 by mnjuly1970 last updated on 20/Sep/22 $$ \\ $$$$\:\:\Omega\:=\:\int_{\mathrm{0}} ^{\:\mathrm{1}} \frac{\:{x}.{tanh}^{\:−\mathrm{1}} \left({x}\right)}{\left(\mathrm{1}+{x}\right)^{\:\mathrm{2}} }{dx}=\:\frac{\mathrm{1}}{\mathrm{24}}\:\left(\pi^{\:\mathrm{2}} −\mathrm{6}\right) \\ $$ Answered by Peace last updated on…
Question Number 45373 by arvinddayama01@gmail.com last updated on 12/Oct/18 $$\int\frac{\mathrm{t}^{\mathrm{3}} }{\mathrm{1}+\mathrm{t}}\mathrm{dt}=? \\ $$ Commented by maxmathsup by imad last updated on 12/Oct/18 $$\int\:\frac{{t}^{\mathrm{3}} }{\mathrm{1}+{t}}{dt}\:=\int\:\frac{{t}^{\mathrm{3}} +\mathrm{1}−\mathrm{1}}{\mathrm{1}+{t}}{dt}\:=\int\:\left({t}^{\mathrm{2}}…
Question Number 110888 by mnjuly1970 last updated on 31/Aug/20 $$\:\:\:\:\:\:\:\:\:\:….{calculus}…. \\ $$$${please}\:{solve}\:: \\ $$$$ \\ $$$$\Omega_{\mathrm{1}} =\int_{\mathrm{0}} ^{\:\frac{\pi}{\mathrm{4}}} \left(\sqrt{{tan}\left({x}\right)}\:+\sqrt{{cot}\left({x}\right)}\:\right){dx}=?? \\ $$$$\:\Omega_{\mathrm{2}} =\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{4}}} {tan}\left({x}\right){ln}\left(\left(\mathrm{1}+{tan}^{\mathrm{2}} \left({x}\right)\right)\right){dx}\:=??…
Question Number 45352 by Meritguide1234 last updated on 12/Oct/18 Answered by tanmay.chaudhury50@gmail.com last updated on 12/Oct/18 $${x}−{y}=\frac{{x}^{\mathrm{2}} }{{y}^{\mathrm{2}} } \\ $$$${y}\left(\frac{{x}}{{y}}−\mathrm{1}\right)=\frac{{x}^{\mathrm{2}} }{{y}^{\mathrm{2}} }\:\:\:\:\:\:\:{t}=\frac{{x}}{{y}} \\ $$$${y}\left({t}−\mathrm{1}\right)={t}^{\mathrm{2}}…
Question Number 176421 by mnjuly1970 last updated on 18/Sep/22 Answered by topollonaketsana last updated on 18/Sep/22 $$ \\ $$ Answered by topollonaketsana last updated on…