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Category: Integration

Question-46639

Question Number 46639 by Tinkutara last updated on 29/Oct/18 Commented by maxmathsup by imad last updated on 30/Oct/18 $${let}\:{A}\:=\int_{\mathrm{0}} ^{\pi} \:\:\frac{{sin}\left(\mathrm{2}{x}\right)}{{x}+\mathrm{1}}{dx}\:\:\:\Rightarrow{A}=_{\mathrm{2}{x}={t}} \:\:\:\int_{\mathrm{0}} ^{\mathrm{2}\pi} \:\:\frac{{sin}\left({t}\right)}{\frac{{t}}{\mathrm{2}}+\mathrm{1}}\:\frac{{dt}}{\mathrm{2}} \