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Category: Integration

Question-46499

Question Number 46499 by Tawa1 last updated on 27/Oct/18 Answered by MJS last updated on 27/Oct/18 6sinxcos2x+sin2x23sinx(1cosx)2(5sin2x)dx=$$=\int\frac{\mathrm{6cos}^{\mathrm{2}} \:{x}\:+\mathrm{2cos}\:{x}\:−\mathrm{23}}{\left(\mathrm{1}−\mathrm{cos}\:{x}\right)^{\mathrm{2}} \left(\mathrm{4}+\mathrm{cos}^{\mathrm{2}} \:{x}\right)}\mathrm{sin}\:{x}\:{dx}=…