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Category: Integration

let-f-x-x-e-t-t-dt-1-calculate-f-x-2-find-a-equivalent-of-f-x-when-x-

Question Number 44318 by abdo.msup.com last updated on 26/Sep/18 $${let}\:{f}\left({x}\right)=\int_{{x}} ^{+\infty} \:\frac{{e}^{−{t}} }{{t}}{dt} \\ $$$$\left.\mathrm{1}\right){calculate}\:{f}^{'} \left({x}\right) \\ $$$$\left.\mathrm{2}\right){find}\:{a}\:{equivalent}\:{of}\:{f}\left({x}\right)\:{when} \\ $$$${x}\rightarrow+\infty. \\ $$ Commented by tanmay.chaudhury50@gmail.com…

J-0-pi-2-sin-x-1-sin-x-cos-x-dx-

Question Number 175387 by cortano1 last updated on 29/Aug/22 $$\:{J}=\underset{\mathrm{0}} {\overset{\pi/\mathrm{2}} {\int}}\:\frac{\mathrm{sin}\:{x}}{\mathrm{1}+\mathrm{sin}\:{x}+\mathrm{cos}\:{x}}\:{dx} \\ $$ Commented by infinityaction last updated on 29/Aug/22 $$\:\:\:\:{J}\:\:\:=\:\int_{\mathrm{0}} ^{\pi/\mathrm{2}} \frac{\mathrm{2sin}\frac{{x}}{\mathrm{2}}\mathrm{cos}\:\frac{{x}}{\mathrm{2}}\:}{\mathrm{2sin}\frac{{x}}{\mathrm{2}}\:\mathrm{cos}\frac{{x}}{\mathrm{2}}\:+\mathrm{2cos}^{\mathrm{2}} \frac{{x}}{\mathrm{2}}\:}{dx}…

find-the-value-of-I-cos-t-x-2-x-1-2-dx-from-R-2-calculate-dx-x-2-x-1-2-

Question Number 44309 by abdo.msup.com last updated on 26/Sep/18 $${find}\:{the}\:{value}\:{of}\: \\ $$$${I}\:=\int_{−\infty} ^{+\infty} \:\:\:\:\frac{{cos}\left(\alpha{t}\right)}{\left({x}^{\mathrm{2}} \:+{x}\:+\mathrm{1}\right)^{\mathrm{2}} }{dx} \\ $$$$\alpha\:{from}\:{R}. \\ $$$$\left.\mathrm{2}\right){calculate}\:\int_{−\infty} ^{+\infty} \:\:\:\frac{{dx}}{\left({x}^{\mathrm{2}} \:+{x}\:+\mathrm{1}\right)^{\mathrm{2}} } \\…

let-I-0-cos-4-t-e-2t-dt-and-J-0-sin-4-t-e-2t-dt-1-calculate-I-J-and-I-J-2-find-the-values-of-I-and-J-

Question Number 44308 by abdo.msup.com last updated on 26/Sep/18 $${let}\:{I}\:=\:\int_{\mathrm{0}} ^{\infty} \:{cos}^{\mathrm{4}} {t}\:{e}^{−\mathrm{2}{t}} {dt}\:{and}\:{J}=\int_{\mathrm{0}} ^{\infty} \:{sin}^{\mathrm{4}} {t}\:{e}^{−\mathrm{2}{t}} {dt} \\ $$$$\left.\mathrm{1}\right)\:{calculate}\:{I}\:+{J}\:{and}\:{I}−{J} \\ $$$$\left.\mathrm{2}\right){find}\:{the}\:{values}\:{of}\:{I}\:{and}\:{J}. \\ $$ Commented…