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Category: Integration

A-curve-passes-through-the-point-1-11-and-its-gradient-at-any-point-is-ax-2-b-where-a-and-b-are-constants-The-tangent-to-the-curve-at-the-point-2-16-is-parallel-to-the-x-axis-Find-i-the-val

Question Number 43923 by pieroo last updated on 17/Sep/18 $$\mathrm{A}\:\mathrm{curve}\:\mathrm{passes}\:\mathrm{through}\:\mathrm{the}\:\mathrm{point}\:\left(\mathrm{1},−\mathrm{11}\right)\:\mathrm{and}\:\mathrm{its} \\ $$$$\mathrm{gradient}\:\mathrm{at}\:\mathrm{any}\:\mathrm{point}\:\mathrm{is}\:\boldsymbol{\mathrm{a}}\mathrm{x}^{\mathrm{2}} +\boldsymbol{\mathrm{b}},\:\mathrm{where}\:\boldsymbol{\mathrm{a}}\:\mathrm{and}\:\boldsymbol{\mathrm{b}}\:\mathrm{are} \\ $$$$\mathrm{constants}.\:\mathrm{The}\:\mathrm{tangent}\:\mathrm{to}\:\mathrm{the}\:\mathrm{curve}\:\mathrm{at}\:\mathrm{the}\:\mathrm{point} \\ $$$$\left(\mathrm{2},−\mathrm{16}\right)\:\mathrm{is}\:\mathrm{parallel}\:\mathrm{to}\:\mathrm{the}\:\boldsymbol{\mathrm{x}}-\mathrm{axis}.\:\mathrm{Find} \\ $$$$\mathrm{i}.\:\mathrm{the}\:\mathrm{values}\:\mathrm{of}\:\boldsymbol{\mathrm{a}}\:\mathrm{and}\:\boldsymbol{\mathrm{b}} \\ $$$$\mathrm{ii}.\:\mathrm{the}\:\mathrm{equation}\:\mathrm{of}\:\mathrm{the}\:\mathrm{curve} \\ $$ Answered by…

1-find-f-x-0-x-ln-t-ln-1-t-dt-with-0-x-1-2-find-the-value-of-0-1-ln-t-ln-1-t-dt-

Question Number 43918 by maxmathsup by imad last updated on 17/Sep/18 $$\left.\mathrm{1}\right)\:{find}\:{f}\left({x}\right)\:=\int_{\mathrm{0}} ^{{x}} {ln}\left({t}\right){ln}\left(\mathrm{1}−{t}\right){dt}\:\:\:{with}\:\mathrm{0}\leqslant{x}\leqslant\mathrm{1} \\ $$$$\left.\mathrm{2}\right)\:{find}\:{the}\:{value}\:{of}\:\int_{\mathrm{0}} ^{\mathrm{1}} {ln}\left({t}\right){ln}\left(\mathrm{1}−{t}\right){dt}\:. \\ $$ Commented by maxmathsup by imad…

find-x-1-cosx-dx-

Question Number 43914 by maxmathsup by imad last updated on 17/Sep/18 $${find}\:\int\:\:\:\:\frac{{x}}{\:\sqrt{\mathrm{1}+{cosx}}}{dx}\:. \\ $$ Commented by maxmathsup by imad last updated on 19/Sep/18 $${let}\:{A}\:=\:\int\:\:\:\:\:\frac{{x}}{\:\sqrt{\mathrm{1}+{cosx}}}{dx}\:{we}\:{have}\:{A}\:=\:\int\:\:\:\frac{{x}}{\:\sqrt{\mathrm{2}{cos}^{\mathrm{2}} \left(\frac{{x}}{\mathrm{2}}\right)}}{dx}…

find-f-a-t-0-2pi-dx-a-t-sinx-2-calculate-0-2pi-sinx-a-tsinx-2-dx-3-calculate-0-2pi-dx-a-tsinx-2-

Question Number 43909 by abdo.msup.com last updated on 17/Sep/18 $${find}\:{f}\left({a},{t}\right)=\int_{\mathrm{0}} ^{\mathrm{2}\pi} \:\:\:\frac{{dx}}{{a}\:+{t}\:{sinx}} \\ $$$$\left.\mathrm{2}\right){calculate}\:\int_{\mathrm{0}} ^{\mathrm{2}\pi} \:\frac{{sinx}}{\left({a}+{tsinx}\right)^{\mathrm{2}} }{dx} \\ $$$$\left.\mathrm{3}\right){calculate}\:\int_{\mathrm{0}} ^{\mathrm{2}\pi} \:\:\frac{{dx}}{\left({a}+{tsinx}\right)^{\mathrm{2}} }\:. \\ $$ Answered…