Question Number 43907 by abdo.msup.com last updated on 17/Sep/18 $${find}\:\int\:\:\frac{{cos}^{\mathrm{2}} {x}\:−{sin}^{\mathrm{2}} {x}}{\mathrm{3}\:+{tan}^{\mathrm{2}} {x}}{dx} \\ $$ Commented by maxmathsup by imad last updated on 18/Sep/18 $${let}\:{I}\:=\:\int\:\:\frac{{cos}^{\mathrm{2}}…
Question Number 43904 by abdo.msup.com last updated on 17/Sep/18 $${calculate}\:\:\int_{\mathrm{0}} ^{\infty} \:\:\frac{\left(\mathrm{1}+{x}\right)^{\frac{\mathrm{1}}{\mathrm{3}}} −\mathrm{1}}{{x}\left(\mathrm{1}+{x}\right)^{\frac{\mathrm{2}}{\mathrm{3}}} }{dx} \\ $$ Commented by maxmathsup by imad last updated on 19/Sep/18…
Question Number 43905 by abdo.msup.com last updated on 17/Sep/18 $${calculate}\:\int_{\mathrm{1}} ^{+\infty} \:\:\frac{{dx}}{{x}^{\mathrm{3}} \sqrt{\mathrm{2}+{x}^{\mathrm{2}} }} \\ $$ Commented by maxmathsup by imad last updated on 18/Sep/18…
Question Number 109435 by shahria14 last updated on 23/Aug/20 Answered by mnjuly1970 last updated on 23/Aug/20 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 174965 by cortano1 last updated on 15/Aug/22 $$\:\:\:\:\:\:\int\:\frac{{x}+\mathrm{sin}\:{x}}{\mathrm{1}+\mathrm{cos}\:{x}}\:{dx}\:=? \\ $$ Answered by som(math1967) last updated on 15/Aug/22 $$\int\frac{{x}}{\mathrm{2}{cos}^{\mathrm{2}} \frac{{x}}{\mathrm{2}}}{dx}+\int\frac{\mathrm{2}{sin}\frac{{x}}{\mathrm{2}}{cos}\frac{{x}}{\mathrm{2}}}{\mathrm{2}{cos}^{\mathrm{2}} \frac{{x}}{\mathrm{2}}}{dx} \\ $$$$\frac{\mathrm{1}}{\mathrm{2}}\int{xsec}^{\mathrm{2}} \frac{{x}}{\mathrm{2}}{dx}\:+\int{tan}\frac{{x}}{\mathrm{2}}{dx}…
Question Number 43861 by Tinkutara last updated on 16/Sep/18 $$\int\mathrm{sin}^{\mathrm{3}} \:\sqrt{{x}}\:{dx} \\ $$ Commented by Tinkutara last updated on 16/Sep/18 $${Answer}\:{given}\:{is} \\ $$$$−\mathrm{3}{x}^{\mathrm{3}/\mathrm{2}} \mathrm{cos}^{\mathrm{3}} \:\sqrt{{x}}\:+\mathrm{6}{x}^{\mathrm{1}/\mathrm{3}}…
Question Number 109378 by shahria14 last updated on 23/Aug/20 Answered by john santu last updated on 23/Aug/20 $$\:\:\:\:\:\frac{\approx{JS}\:\approx}{\blacksquare\bigstar\blacksquare} \\ $$$$\sqrt{\frac{\mathrm{1}+{x}}{\mathrm{1}−{x}}.\frac{\mathrm{1}+{x}}{\mathrm{1}+{x}}}\:=\:\frac{\mathrm{1}+{x}}{\:\sqrt{\mathrm{1}−{x}^{\mathrm{2}} }}\: \\ $$$$\int\:\sqrt{\frac{\mathrm{1}+{x}}{\mathrm{1}−{x}}}\:{dx}\:=\:\int\:\frac{\mathrm{1}}{\:\sqrt{\mathrm{1}−{x}^{\mathrm{2}} }}\:{dx}\:+\int\:\frac{{x}}{\:\sqrt{\mathrm{1}−{x}^{\mathrm{2}} }}\:{dx}…
Question Number 43840 by peter frank last updated on 16/Sep/18 Commented by maxmathsup by imad last updated on 16/Sep/18 $${let}\:{I}\:=\:\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} \:\:\:\frac{{sin}^{\mathrm{4}} {x}}{{cos}^{\mathrm{4}} {x}\:+{sin}^{\mathrm{4}} {x}}{dx}\:\:{and}\:{J}\:=\:\int_{\mathrm{0}}…
Question Number 109366 by mnjuly1970 last updated on 23/Aug/20 Commented by 150505R last updated on 24/Aug/20 $${answer}\:{is}\:−\frac{\pi}{\mathrm{8}}{log}\mathrm{2}\:\:…….{small}\:{mistake}\:…. \\ $$$$ \\ $$ Terms of Service Privacy…
Question Number 43832 by physics last updated on 16/Sep/18 Commented by physics last updated on 16/Sep/18 $${do}\:{with}\:{full}\:{explanation}\:{please} \\ $$ Commented by maxmathsup by imad last…