Question Number 108921 by Ar Brandon last updated on 20/Aug/20 $$\mathrm{a}.\:\:\int\frac{\mathrm{sin}^{\mathrm{3}} \mathrm{4x}}{\mathrm{cos}^{\mathrm{8}} \mathrm{4x}}\mathrm{dx} \\ $$$$\mathrm{b}.\:\:\int_{−\frac{\pi}{\mathrm{2}}} ^{\frac{\pi}{\mathrm{2}}} \left(\mathrm{x}^{\mathrm{2}} \mathrm{e}^{\mathrm{cosx}} −\mathrm{2x}\right)\mathrm{sinxdx} \\ $$ Answered by bobhans last…
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Question Number 108893 by bobhans last updated on 20/Aug/20 $$\left(\mathrm{1}\right)\int\:\frac{{x}^{\mathrm{4}} }{\mathrm{1}−{x}^{\mathrm{2}} }\:{dx}\: \\ $$$$\left(\mathrm{2}\right)\underset{−\mathrm{3}} {\overset{\mathrm{5}} {\int}}\sqrt{\mid{x}\mid^{\mathrm{3}} }\:{dx}\: \\ $$$$\left(\mathrm{3}\right)\:\underset{\mathrm{0}} {\overset{\frac{\pi^{\mathrm{2}} }{\mathrm{4}}} {\int}}\:\mathrm{sin}\:\sqrt{{x}}\:{dx}\: \\ $$$$\left(\mathrm{4}\right)\:\underset{−\infty} {\overset{\infty}…
Question Number 43354 by pieroo last updated on 10/Sep/18 $$\mathrm{A}\:\mathrm{particle}\:\mathrm{starts}\:\mathrm{from}\:\mathrm{rest}\:\mathrm{with}\:\mathrm{acceleration}\left(\mathrm{30}+\mathrm{6t}\right) \\ $$$$\mathrm{ms}^{−\mathrm{2}} \:\mathrm{at}\:\mathrm{time}\:\mathrm{t}.\:\mathrm{Where}\:\mathrm{will}\:\mathrm{the}\:\mathrm{particle}\:\mathrm{come}\:\mathrm{to}\:\mathrm{rest} \\ $$$$\mathrm{again}? \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 10/Sep/18 $$\frac{{dv}}{{dt}}=\mathrm{30}+\mathrm{6}{t}…
Question Number 108891 by bobhans last updated on 20/Aug/20 $$\:\:\:\frac{\boldsymbol{{bob}}\mathbb{H}{ans}}{\nparallel} \\ $$$$\int\:\frac{\left({x}^{\mathrm{2}} −\mathrm{2}\right)\:{dx}}{\left({x}^{\mathrm{4}} +\mathrm{5}{x}^{\mathrm{2}} +\mathrm{4}\right)\:\mathrm{arc}\:\mathrm{tan}\:\left(\frac{{x}^{\mathrm{2}} +\mathrm{2}}{{x}}\right)} \\ $$ Answered by bemath last updated on 20/Aug/20…
Question Number 174421 by ali009 last updated on 31/Jul/22 $$\left.\mathrm{1}\right)\:{show}\:{that} \\ $$$$\int_{−\mathrm{1}} ^{\mathrm{1}} \frac{−{dx}}{\:\sqrt{{x}^{\mathrm{2}} +\mathrm{2}{x}+\mathrm{2}}}={ln}\left(\sqrt{\mathrm{5}}−\mathrm{2}\right) \\ $$$$\left.\mathrm{2}\right) \\ $$$${determine} \\ $$$$\int_{\mathrm{1}} ^{\infty} \frac{{dx}}{\left({x}+\mathrm{1}\right)\sqrt{{x}}} \\ $$$$\left.\mathrm{3}\right)\:{test}\:{the}\:{convergence}\:{of}\:{the}\:{series}\:{given}\:{by}…
Question Number 174420 by ali009 last updated on 31/Jul/22 $${determine}\:{whether}\:{the}\:{following}\:{integral} \\ $$$${are}\:{convergence}\:{or}\:{divergence} \\ $$$$\left.\mathrm{1}\right)\int_{−\infty} ^{\mathrm{1}} \frac{\mathrm{3}}{\mathrm{4}−\mathrm{2}{x}}{dx} \\ $$$$\left.\mathrm{2}\right)\int_{\mathrm{1}} ^{\mathrm{2}} \frac{{x}^{\mathrm{2}} }{\:\sqrt{\mathrm{8}−{x}^{\mathrm{3}} }}{dx} \\ $$ Answered…
Question Number 174419 by ali009 last updated on 31/Jul/22 $${solve} \\ $$$$\int\frac{{e}^{{sinh}^{−\mathrm{1}} \left({x}+\mathrm{3}\right)} }{\:\sqrt{\mathrm{2}{x}^{\mathrm{2}} +\mathrm{12}{x}+\mathrm{20}}}{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 43342 by pieroo last updated on 10/Sep/18 $$\mathrm{using}\:\mathrm{the}\:\mathrm{substitution}\:\mathrm{u}=\mathrm{x}+\mathrm{2},\:\mathrm{evaluate}\:\int_{\mathrm{1}} ^{\mathrm{2}} \frac{\mathrm{x}−\mathrm{1}}{\left(\mathrm{x}+\mathrm{2}\right)^{\mathrm{4}} } \\ $$ Answered by $@ty@m last updated on 10/Sep/18 $$\underset{\mathrm{3}} {\overset{\mathrm{4}} {\int}}\frac{\left({u}−\mathrm{2}\right)−\mathrm{1}}{{u}^{\mathrm{4}}…