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Category: Integration

Question-43419

Question Number 43419 by Raj Singh last updated on 10/Sep/18 Commented by maxmathsup by imad last updated on 10/Sep/18 $${let}\:{A}\:=\:\int\:\:\frac{{xdx}}{\left({x}−\mathrm{1}\right)\left({x}^{\mathrm{2}} +\mathrm{1}\right)^{\mathrm{2}} } \\ $$$${A}\:=\:\int\:\:\frac{{x}−\mathrm{1}+\mathrm{1}}{\left({x}−\mathrm{1}\right)\left({x}^{\mathrm{2}} \:+\mathrm{1}\right)^{\mathrm{2}}…

Question-43386

Question Number 43386 by ajfour last updated on 10/Sep/18 Commented by ajfour last updated on 10/Sep/18 $${If}\:{the}\:{two}\:{differently}\:{shaded} \\ $$$${areas}\:{are}\:{equal},\:{find}\:{slope}\:\boldsymbol{{m}}\:{of} \\ $$$${line},\:{in}\:{terms}\:{of}\:\boldsymbol{{a}}. \\ $$ Commented by…

a-sin-3-4x-cos-8-4x-dx-b-pi-2-pi-2-x-2-e-cosx-2x-sinxdx-

Question Number 108921 by Ar Brandon last updated on 20/Aug/20 $$\mathrm{a}.\:\:\int\frac{\mathrm{sin}^{\mathrm{3}} \mathrm{4x}}{\mathrm{cos}^{\mathrm{8}} \mathrm{4x}}\mathrm{dx} \\ $$$$\mathrm{b}.\:\:\int_{−\frac{\pi}{\mathrm{2}}} ^{\frac{\pi}{\mathrm{2}}} \left(\mathrm{x}^{\mathrm{2}} \mathrm{e}^{\mathrm{cosx}} −\mathrm{2x}\right)\mathrm{sinxdx} \\ $$ Answered by bobhans last…

1-x-4-1-x-2-dx-2-3-5-x-3-dx-3-0-pi-2-4-sin-x-dx-4-e-2x-2-5x-3-dx-5-x-3-y-2x-2-y-2xy-8y-0-6-x-4-y-4-dx-2x-3-y-dy-0-7-2-xy-y-

Question Number 108893 by bobhans last updated on 20/Aug/20 $$\left(\mathrm{1}\right)\int\:\frac{{x}^{\mathrm{4}} }{\mathrm{1}−{x}^{\mathrm{2}} }\:{dx}\: \\ $$$$\left(\mathrm{2}\right)\underset{−\mathrm{3}} {\overset{\mathrm{5}} {\int}}\sqrt{\mid{x}\mid^{\mathrm{3}} }\:{dx}\: \\ $$$$\left(\mathrm{3}\right)\:\underset{\mathrm{0}} {\overset{\frac{\pi^{\mathrm{2}} }{\mathrm{4}}} {\int}}\:\mathrm{sin}\:\sqrt{{x}}\:{dx}\: \\ $$$$\left(\mathrm{4}\right)\:\underset{−\infty} {\overset{\infty}…

A-particle-starts-from-rest-with-acceleration-30-6t-ms-2-at-time-t-Where-will-the-particle-come-to-rest-again-

Question Number 43354 by pieroo last updated on 10/Sep/18 $$\mathrm{A}\:\mathrm{particle}\:\mathrm{starts}\:\mathrm{from}\:\mathrm{rest}\:\mathrm{with}\:\mathrm{acceleration}\left(\mathrm{30}+\mathrm{6t}\right) \\ $$$$\mathrm{ms}^{−\mathrm{2}} \:\mathrm{at}\:\mathrm{time}\:\mathrm{t}.\:\mathrm{Where}\:\mathrm{will}\:\mathrm{the}\:\mathrm{particle}\:\mathrm{come}\:\mathrm{to}\:\mathrm{rest} \\ $$$$\mathrm{again}? \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on 10/Sep/18 $$\frac{{dv}}{{dt}}=\mathrm{30}+\mathrm{6}{t}…

bobHans-x-2-2-dx-x-4-5x-2-4-arc-tan-x-2-2-x-

Question Number 108891 by bobhans last updated on 20/Aug/20 $$\:\:\:\frac{\boldsymbol{{bob}}\mathbb{H}{ans}}{\nparallel} \\ $$$$\int\:\frac{\left({x}^{\mathrm{2}} −\mathrm{2}\right)\:{dx}}{\left({x}^{\mathrm{4}} +\mathrm{5}{x}^{\mathrm{2}} +\mathrm{4}\right)\:\mathrm{arc}\:\mathrm{tan}\:\left(\frac{{x}^{\mathrm{2}} +\mathrm{2}}{{x}}\right)} \\ $$ Answered by bemath last updated on 20/Aug/20…