Category: Integration

Question Number 109642 by malwan last updated on 24/Aug/20 Answered by Dwaipayan Shikari last updated on 24/Aug/20 $$\int \frac{dx}{\sqrt{2{tan}^2\theta +2}}\frac{\sqrt{2}}{5}{sec}^2\theta d\theta x=\frac{\sqrt{2}}{5}tan\theta$$$$\frac{1}{5}\int sec\theta d\theta$$$$\frac{\mathrm{1}}{\mathrm{5}}{log}\left({sec}\theta+{tan}\theta\right)=\frac{\mathrm{1}}{\mathrm{5}}{log}\left(\sqrt{\frac{\mathrm{25}{x}^{\mathrm{2}} +\mathrm{1}}{\mathrm{2}}}\:+\frac{\mathrm{5}{x}}{\:\sqrt{\mathrm{2}}}\right)+{C}…

Question Number 109616 by mathmax by abdo last updated on 24/Aug/20 $$\mathrm{find}{\int }_0^1\sqrt{1+{\mathrm{x}}^4}\mathrm{dx}$$ Commented by mathdave last updated on 24/Aug/20 $${this}\:{is}\:{hypergeometric}\:{question}\:{or}\:{question}…

Question Number 109546 by bemath last updated on 24/Aug/20 $$Iff\left(x\right)continuein[1,30]and$$$$\underset{6}{\stackrel{30}{\int }}f\left(x\right)dx=30,then\underset{1}{\stackrel{9}{\int }}f(3y+3)dy=\mathrm{\_}\mathrm{\_}$$ Commented by kaivan.ahmadi last updated on 24/Aug/20…

Question Number 44001 by maxmathsup by imad last updated on 19/Sep/18 $$calculateA={\int }_0^1\frac{x}{arctanx}dx.{\int }_0^1\frac{arctanx}{x}dx$$ Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 43999 by maxmathsup by imad last updated on 19/Sep/18 $$findthevalueof{\int }_0^{\frac{\pi }{2}}\frac{x}{\sqrt{1-cosx}}dx.$$ Commented by maxmathsup by imad last updated on 20/Sep/18…