Category: Integration

Question Number 108893 by bobhans last updated on 20/Aug/20 $$\left(1\right)\int \frac{x^4}{1-x^2}dx$$$$\left(2\right)\underset{-3}{\stackrel{5}{\int }}\sqrt{\mid x{\mid }^3}dx$$$$\left(3\right)\underset{0}{\stackrel{\frac{{\pi }^2}{4}}{\int }}\sin \sqrt{x}dx$$$$\left(\mathrm{4}\right)\:\underset{−\infty} {\overset{\infty}…

Question Number 108891 by bobhans last updated on 20/Aug/20 $$\frac{\mathit{b}\mathit{o}\mathit{b}\mathbb{H}ans}{\nparallel }$$$$\int \frac{(x^2-2)dx}{(x^4+5x^2+4)\mathrm{arc}\tan \left(\frac{x^2+2}{x}\right)}$$ Answered by bemath last updated on 20/Aug/20…

Question Number 174420 by ali009 last updated on 31/Jul/22 $$determinewhetherthefollowingintegral$$$$areconvergenceordivergence$$$$1){\int }_{-\mathrm{\infty }}^1\frac{3}{4-2x}dx$$$$2){\int }_1^2\frac{x^2}{\sqrt{8-x^3}}dx$$ Answered…

Question Number 43342 by pieroo last updated on 10/Sep/18 $$\mathrm{using}\mathrm{the}\mathrm{substitution}\mathrm{u}=\mathrm{x}+2,\mathrm{evaluate}{\int }_1^2\frac{\mathrm{x}-1}{{(\mathrm{x}+2)}^4}$$ Answered by $@ty@mlastupdatedon10/Sep/18$$\underset{\mathrm{3}} {\overset{\mathrm{4}} {\int}}\frac{\left({u}−\mathrm{2}\right)−\mathrm{1}}{{u}^{\mathrm{4}}…

Question Number 43324 by Raj Singh last updated on 09/Sep/18 Answered by tanmay.chaudhury50@gmail.com last updated on 09/Sep/18 $$\frac{1}{2}\int \frac{x^2+1+x^2-1}{(x^2-1)(x^2+1)}dx$$$$\frac{\mathrm{1}}{\mathrm{2}}\int\frac{{dx}}{{x}^{\mathrm{2}} −\mathrm{1}}+\frac{\mathrm{1}}{\mathrm{2}}\int\frac{{dx}}{{x}^{\mathrm{2}}…