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Category: Integration

Question-108748

Question Number 108748 by john santu last updated on 18/Aug/20 Answered by bemath last updated on 19/Aug/20 byparts{u=ln(sinx)du=cosxsinxdxv=sinxdx=cosxJ=cosxln(sinx)+cos2xdxsinx$${J}=−\mathrm{cos}\:{x}\:\mathrm{ln}\:\left(\mathrm{sin}\:{x}\right)+\int\:\frac{\mathrm{1}−\mathrm{sin}\:^{\mathrm{2}}…