Question Number 174096 by mnjuly1970 last updated on 24/Jul/22
Question Number 43027 by Raj Singh last updated on 06/Sep/18 Commented by math khazana by abdo last updated on 07/Sep/18
Question Number 43008 by MJS last updated on 06/Sep/18
Question Number 42994 by MJS last updated on 06/Sep/18
Question Number 108507 by Eric002 last updated on 17/Aug/20
Question Number 108506 by mnjuly1970 last updated on 17/Aug/20 Answered by mathmax by abdo last updated on 17/Aug/20 $$\mathrm{A}\:=\int_{\mathrm{0}} ^{\infty} \:\frac{\mathrm{ln}\left(\mathrm{x}^{\mathrm{2}} +\mathrm{1}\right)}{\mathrm{x}^{\mathrm{2}} \left(\mathrm{x}^{\mathrm{2}} \:+\mathrm{3}\right)}\mathrm{dx}\:\Rightarrow\mathrm{A}\:=_{\mathrm{x}=\sqrt{\mathrm{3}}\mathrm{t}} \:\:\:\int_{\mathrm{0}}…
Question Number 108502 by mnjuly1970 last updated on 17/Aug/20 Commented by mnjuly1970 last updated on 17/Aug/20
Question Number 174024 by Michaelfaraday last updated on 23/Jul/22 Answered by behi834171 last updated on 23/Jul/22 $$\frac{\mathrm{1}}{\left({a}^{\mathrm{2}} +{t}^{\mathrm{2}} \right)\left({b}^{\mathrm{2}} +{t}^{\mathrm{2}} \right)}=\frac{\mathrm{1}}{{a}^{\mathrm{2}} −{b}^{\mathrm{2}} }.\frac{\left({a}^{\mathrm{2}} +{t}^{\mathrm{2}} \right)−\left({b}^{\mathrm{2}}…
Question Number 42945 by ajfour last updated on 05/Sep/18
Question Number 108444 by bobhans last updated on 17/Aug/20