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Category: Integration

BeMath-x-x-2a-x-dx-

Question Number 107965 by bemath last updated on 13/Aug/20 BeMathxx2axdx? Answered by bobhans last updated on 13/Aug/20 BOBHANS\iddotsΠ$$\:\mathrm{I}=\:\int\:\mathrm{x}\:\sqrt{\frac{\mathrm{x}}{\mathrm{2a}−\mathrm{x}}}\:\mathrm{dx}\:\:\left[\:\mathrm{set}\:\mathrm{x}\:=\:\mathrm{a}−\mathrm{acos}\:\mathrm{2t}\:\right] \

0-cos-ax-sin-bx-x-2-dx-0-1-2sin-2-ax-2-1-2sin-2-bx-2-x-2-dx-2-0-sin-bx-2-x-2-dx-1-2-0-

Question Number 173486 by mnjuly1970 last updated on 12/Jul/22 ϕ=0cos(ax)sin(bx)x2dx=?$$\:\:\:\boldsymbol{\phi}=\int_{\mathrm{0}} ^{\:\infty} \frac{\mathrm{1}−\mathrm{2}{sin}^{\:\mathrm{2}} \left(\frac{{ax}}{\mathrm{2}}\right)−\left(\mathrm{1}−\mathrm{2}{sin}^{\:\mathrm{2}} \left(\frac{{bx}}{\mathrm{2}}\right)\right)}{{x}\:^{\mathrm{2}} }{dx} \

1-1-tanx-dx-

Question Number 42407 by Tawa1 last updated on 25/Aug/18 11+tanxdx Commented by maxmathsup by imad last updated on 25/Aug/18 letI=dx1+tanxchangementtanx=tgive$${I}\:\:=\:\int\:\:\:\:\:\frac{\mathrm{1}}{\left(\mathrm{1}+{t}\right)\left({t}^{\mathrm{2}} \:+\mathrm{1}\right)}{dt}\:\:{let}\:{decompose}\:{F}\left({t}\right)\:=\:\:\frac{\mathrm{1}}{\left({t}+\mathrm{1}\right)\left({t}^{\mathrm{2}}…

Question-42370

Question Number 42370 by Raj Singh last updated on 24/Aug/18 Commented by maxmathsup by imad last updated on 24/Aug/18 letA=dxsin(2x)+sinx$${A}\:=\:\int\:\:\:\:\:\frac{{dx}}{\mathrm{2}{sinx}\:{cosx}\:+{sinx}}\:=\:\int\:\:\:\:\:\:\frac{{sinx}}{\mathrm{2}{sin}^{\mathrm{2}} {xcosx}\:+{sin}^{\mathrm{2}} {x}}\:{dx} \