Question Number 172088 by Mikenice last updated on 23/Jun/22 Answered by Joepkollie last updated on 23/Jun/22 $$\:\:\:\boldsymbol{{solution}}.. \\ $$$$\:\:\:\boldsymbol{{y}}=\boldsymbol{\mathrm{e}}^{\boldsymbol{{u}}\:} \Rightarrow\Rightarrow\boldsymbol{{y}}'=\boldsymbol{\mathrm{e}}^{\boldsymbol{{u}}} \bullet\boldsymbol{{u}}' \\ $$$$\:\:\:\:\boldsymbol{{y}}'=\mathrm{cos}\boldsymbol{{x}\mathrm{e}}^{\mathrm{sin}\boldsymbol{{x}}} .. \\…
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Question Number 40952 by Raj Singh last updated on 30/Jul/18 Commented by abdo mathsup 649 cc last updated on 30/Jul/18 $${let}\:{I}\:=\:\int\:\:\:\:\frac{{dx}}{\left(\mathrm{9}−{x}^{\mathrm{2}} \right)^{\frac{\mathrm{3}}{\mathrm{2}}} } \\ $$$${I}\:=_{{x}=\mathrm{3}{sin}\theta}…
Question Number 172013 by Mikenice last updated on 23/Jun/22 $${find}: \\ $$$$\int{xe}^{−{ax}} {ax} \\ $$ Answered by puissant last updated on 23/Jun/22 $${Q}=\int{xe}^{−{ax}} {dx}\:\: \\…
Question Number 172012 by Mikenice last updated on 23/Jun/22 $${find} \\ $$$$\int{e}^{{x}} {sinxdx} \\ $$ Answered by puissant last updated on 23/Jun/22 $${J}=\int{e}^{{x}} {sinxdx} \\…
Question Number 172010 by Mikenice last updated on 23/Jun/22 $${find}\:{integrate}: \\ $$$$\int{xe}^{{x}} {dx} \\ $$ Answered by puissant last updated on 23/Jun/22 $${K}=\int{xe}^{{x}} {dx}\:\:;\:\:\begin{cases}{{u}'={e}^{{x}} }\\{{v}={x}}\end{cases}\Rightarrow\:\begin{cases}{{u}={e}^{{x}}…
Question Number 172011 by Mikenice last updated on 23/Jun/22 $${find}\:{integrate}: \\ $$$$\int{x}^{\mathrm{2}} {e}^{{x}} {dx} \\ $$ Answered by puissant last updated on 23/Jun/22 $${P}\:=\:\int{x}^{\mathrm{2}} {e}^{{x}}…
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Question Number 171971 by ilhamQ last updated on 22/Jun/22 $$\int\frac{{x}}{{x}^{\mathrm{2}} +\mathrm{4}{x}+\mathrm{3}}\:{dx}=… \\ $$ Answered by cortano1 last updated on 22/Jun/22 $$\:\:\frac{{x}}{\left({x}+\mathrm{1}\right)\left({x}+\mathrm{3}\right)}\:=\:\frac{{a}}{{x}+\mathrm{1}}\:+\:\frac{{b}}{{x}+\mathrm{3}} \\ $$$$\:{a}\:=\:\frac{−\mathrm{1}}{−\mathrm{1}+\mathrm{3}}\:=−\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$\:{b}=\frac{−\mathrm{3}}{−\mathrm{3}+\mathrm{1}}\:=\:\frac{\mathrm{3}}{\mathrm{2}}…
Question Number 40892 by abdo.msup.com last updated on 28/Jul/18 $${let}\:{B}\left({x},{y}\right)\:=\int_{\mathrm{0}} ^{\mathrm{1}} {t}^{{x}−\mathrm{1}} \left(\mathrm{1}−{t}\right)^{{y}−\mathrm{1}} {dt} \\ $$$${withx}>\mathrm{0}{and}\:{y}>\mathrm{0}\:{prove}\:{that} \\ $$$${B}\left({x},{y}\right)=\:\frac{\Gamma\left({x}\right).\Gamma\left({y}\right)}{\Gamma\left({x}+{y}\right)} \\ $$ Terms of Service Privacy Policy…