Question Number 106132 by mathmax by abdo last updated on 02/Aug/20 $$\mathrm{find}\:\int_{−\infty} ^{+\infty} \:\mathrm{x}^{\mathrm{2}} \mathrm{e}^{−\mathrm{x}^{\mathrm{2}} } \:\mathrm{ln}\left(\mathrm{1}+\mathrm{x}^{\mathrm{2}} \right)\mathrm{dx} \\ $$$$ \\ $$ Terms of Service…
Question Number 106125 by Ar Brandon last updated on 02/Aug/20 $$\int_{\frac{\pi}{\mathrm{4}}} ^{\pi} \sqrt{\mathrm{1}−\mathrm{sin2}{x}}\:\mathrm{d}{x} \\ $$ Answered by Dwaipayan Shikari last updated on 02/Aug/20 $$\int_{\frac{\pi}{\mathrm{4}}} ^{\pi}…
Question Number 106120 by Her_Majesty last updated on 02/Aug/20 $${question}\:\mathrm{106075}\:{again} \\ $$$$\int\frac{\mathrm{1}+{cosx}}{\left(\mathrm{99}{cosx}−\mathrm{70}{sinx}+\mathrm{210}\right){cosx}−\mathrm{66}{sinx}+\mathrm{110}}{dx}=? \\ $$$${using}\:{t}={tan}\left({x}/\mathrm{2}\right)\:{I}\:{get} \\ $$$$−\mathrm{4}\int\frac{{dt}}{{t}^{\mathrm{4}} +\mathrm{8}{t}^{\mathrm{3}} −\mathrm{22}{t}^{\mathrm{2}} +\mathrm{272}{t}−\mathrm{419}} \\ $$$${can}\:{someone}\:{factorize}\:{the}\:{denominator}? \\ $$ Commented by…
Question Number 40580 by maxmathsup by imad last updated on 24/Jul/18 $${find}\:\:\int_{\mathrm{0}} ^{\infty} \:\:\:\frac{{ln}\left(\mathrm{1}+{ix}\right)}{{x}^{\mathrm{3}} \:+\mathrm{8}}{dx} \\ $$$$ \\ $$ Commented by math khazana by abdo…
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Question Number 106075 by Her_Majesty last updated on 02/Aug/20 $$\int\frac{\mathrm{1}+{cosx}}{\left(\mathrm{99}{cosx}−\mathrm{70}{sinx}+\mathrm{210}\right){cosx}−\mathrm{66}{sinx}+\mathrm{110}}{dx}=? \\ $$ Answered by Dwaipayan Shikari last updated on 02/Aug/20 $${From}\:{wolfram}\:{Alpha} \\ $$ Commented by…
Question Number 171601 by mnjuly1970 last updated on 18/Jun/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 40505 by prof Abdo imad last updated on 23/Jul/18 $${calcilate}\:\int_{\frac{\pi}{\mathrm{6}}} ^{\frac{\pi}{\mathrm{4}}} \:\:\:\frac{{sin}\left({x}\right)}{{cos}\left({x}\right)\:+{cos}\left(\mathrm{2}{x}\right)}{dx} \\ $$ Answered by MJS last updated on 23/Jul/18 $$\mathrm{cos}\:\mathrm{2}{x}=\mathrm{2cos}^{\mathrm{2}} \:{x}\:−\mathrm{1}…
Question Number 171565 by Tawa11 last updated on 17/Jun/22 Commented by infinityaction last updated on 17/Jun/22 $$\:\:\:\:{p}\:\:=\:\:\frac{{x}+\mathrm{1}}{{x}−\mathrm{1}}\:\:\:{then}\:\:\:\frac{\mathrm{1}}{{p}}\:\:=\:\:\frac{{x}−\mathrm{1}}{{x}+\mathrm{1}} \\ $$$$\:\:\:\:\:\:\left({p}^{\mathrm{2}} \:+\:\:\frac{\mathrm{1}}{{p}^{\mathrm{2}} }\:\:−\mathrm{2}\right)^{\mathrm{1}/\mathrm{2}} =\:\:\left({p}−\frac{\mathrm{1}}{{p}}\right)^{\mathrm{2}} \\ $$$$\:\:\:\:\:\:\int_{−\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}} ^{\frac{\mathrm{1}}{\:\sqrt{\mathrm{2}}}}…
Question Number 171560 by mnjuly1970 last updated on 17/Jun/22 $$ \\ $$$$\:\:\:\:\:\mathrm{Nice}\:\:\:\mathrm{Integral} \\ $$$$\:\:\: \\ $$$$\:\:\:\:\:\:\:\:\Omega\:=\:\int_{\mathrm{0}} ^{\:\frac{\pi}{\mathrm{4}}} \frac{\:{tan}\left({x}\right)}{\left(\:{cos}^{\:\mathrm{2}} \left({x}\right)\:\:+\:\mathrm{2}{sin}^{\:\mathrm{2}} \left({x}\right)\right)}{dx}\:= \\ $$ Commented by infinityaction…