Menu Close

Category: Integration

Question-40625

Question Number 40625 by Raj Singh last updated on 25/Jul/18 Answered by MJS last updated on 25/Jul/18 dxx+x3=[t=x6dx=6x56dt]$$=\mathrm{6}\int\frac{{t}^{\mathrm{3}} }{{t}+\mathrm{1}}{dt}=\mathrm{6}\int\left({t}^{\mathrm{2}} −{t}+\mathrm{1}−\frac{\mathrm{1}}{{t}+\mathrm{1}}\right){dt}=…