Question Number 104928 by bobhans last updated on 24/Jul/20 $$\int\:\left({e}^{{x}} −\left(\mathrm{2}{x}+\mathrm{3}\right)^{\mathrm{4}} \right)^{\mathrm{3}} \:{dx} \\ $$ Commented by kaivan.ahmadi last updated on 24/Jul/20 $$\int\left({e}^{\mathrm{3}{x}} −\mathrm{3}{e}^{\mathrm{2}{x}} \left(\mathrm{2}{x}+\mathrm{3}\right)^{\mathrm{4}}…
Question Number 39389 by maxmathsup by imad last updated on 05/Jul/18 $${calculate}\:{F}\left({x}\right)\:=\:\int_{\mathrm{0}} ^{\infty} \:\:\:\:\:\:\frac{{dt}}{\mathrm{1}+\left(\mathrm{1}+{x}\left(\mathrm{1}+{t}^{\mathrm{2}} \right)\right)^{\mathrm{2}} } \\ $$ Commented by prof Abdo imad last updated…
Question Number 39386 by maxmathsup by imad last updated on 05/Jul/18 $${find}\:{the}\:{value}\:{of}\:\:\:\int_{\mathrm{0}} ^{\mathrm{1}} \:\:\:\:\frac{{ln}\left(\mathrm{1}+{x}\right)}{\mathrm{1}+{x}^{\mathrm{2}} }{dx} \\ $$ Commented by abdo mathsup 649 cc last updated…
Question Number 39384 by rahul 19 last updated on 05/Jul/18 $$\mathrm{The}\:\mathrm{values}\:\mathrm{of}\:\mathrm{a}\:\mathrm{for}\:\mathrm{which}\:\mathrm{y}=\:\mathrm{a}{x}^{\mathrm{2}} +{ax}+\frac{\mathrm{1}}{\mathrm{24}} \\ $$$${and}\:{x}\:=\:{ay}^{\mathrm{2}} +{ay}+\frac{\mathrm{1}}{\mathrm{24}}\:{touch}\:{each}\:{other} \\ $$$${are} \\ $$$$\left.\mathrm{1}\left.\right)\:\frac{\mathrm{2}}{\mathrm{3}}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{2}\right)\:\frac{\mathrm{3}}{\mathrm{2}} \\ $$$$\left.\mathrm{3}\left.\right)\:\frac{\mathrm{13}+\sqrt{\mathrm{601}}}{\mathrm{12}}\:\:\:\:\:\:\:\mathrm{4}\right)\:\frac{\mathrm{13}−\sqrt{\mathrm{601}}}{\mathrm{12}}. \\ $$ Answered by…
Question Number 39383 by maxmathsup by imad last updated on 05/Jul/18 $${calculate}\:\:\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{3}}} \:\:\:\:\:\:\frac{{sinxdx}}{{cosx}\left(\mathrm{2}+{ln}\left({cosx}\right)\right.}\:. \\ $$ Commented by math khazana by abdo last updated on…
Question Number 39381 by rahul 19 last updated on 05/Jul/18 Answered by ajfour last updated on 06/Jul/18 $${f}\:'\left({x}\right)\geqslant\left[{f}\left({x}\right)\right]^{\mathrm{3}} +\left[{f}\left({x}\right)\right]^{−\mathrm{1}} \\ $$$${and}\:{f}\left(\mathrm{0}\right)=\mathrm{1}\:,\:\:{f}\left({a}\right)=\mathrm{3}^{\mathrm{1}/\mathrm{4}} \\ $$$$\Rightarrow\:\:\:\int_{\mathrm{1}} ^{\:\:{y}} \frac{{dy}}{{y}^{\mathrm{3}}…
Question Number 39382 by rahul 19 last updated on 05/Jul/18 Answered by ajfour last updated on 06/Jul/18 $$\int_{\alpha} ^{\:\:\beta} {f}\left({x}\right){g}'\left({x}\right){dx}\:=\left[{f}\left({x}\right){g}\left({x}\right)\right]_{\alpha} ^{\beta} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:−\int_{\alpha} ^{\:\:\beta} {f}\:'\left({x}\right){g}\left({x}\right){dx}…
Question Number 39379 by rahul 19 last updated on 05/Jul/18 Commented by MJS last updated on 06/Jul/18 $$\left(\mathrm{1}\right)\:\:\:\:\:\mid\mid{x}\mid−\mid{y}\mid\mid=\mathrm{1} \\ $$$$\left(\mathrm{2}\right)\:\:\:\:\:\mathrm{2}{a}\mid{x}\mid\mid{y}\mid+\mathrm{1}=\mathrm{2}\mid{x}\mid+{a}\mid{y}\mid \\ $$$$\left(\mathrm{1}\right)\:\:\:\:\:\begin{cases}{\left.{y}_{\mathrm{1}} \left.=−\mid{x}\mid−\mathrm{1};\:\mathrm{range}\left({y}_{\mathrm{1}} \right)=\right]−\infty;\:−\mathrm{1}\right]}\\{{y}_{\mathrm{2}} =\mid{x}\mid+\mathrm{1};\:\mathrm{range}\left({y}_{\mathrm{2}}…
Question Number 104910 by Dwaipayan Shikari last updated on 24/Jul/20 $$\int_{\mathrm{0}} ^{\mathrm{1}} \frac{\mathrm{1}}{\:\sqrt{\mathrm{1}+{x}^{\mathrm{3}} }}{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 39373 by maxmathsup by imad last updated on 05/Jul/18 $${find}\:{the}\:{values}\:{of}\:{integrals} \\ $$$${A}\:=\:\int_{−\infty} ^{+\infty} \:{cos}\left({x}^{\mathrm{2}} \:+{x}+\mathrm{1}\right){dx}\:\:\:{and}\:{B}\:=\:\int_{−\infty} ^{+\infty} \:{sin}\left({x}^{\mathrm{2}} \:+{x}+\mathrm{1}\right){dx} \\ $$ Commented by math…