Question Number 41847 by maxmathsup by imad last updated on 13/Aug/18 $${let}\:{f}\left({x}\right)\:=\:\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{4}}} \:\:\:\:\:\frac{{dt}}{{x}\:+{tan}\left({t}\right)} \\ $$$$\left.\mathrm{1}\right)\:{find}\:{anoher}\:{expression}\:{off}\:\left({x}\right) \\ $$$$\left.\mathrm{2}\right)\:{calculate}\:\:\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{4}}} \:\:\frac{{dt}}{\mathrm{2}+{tan}\left({t}\right)}\:\:\:{and}\:\:{A}\left(\theta\right)\:=\:\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{4}}} \:\:\:\:\frac{{dt}}{{sin}\theta+{tant}} \\ $$$$\left.\mathrm{3}\right)\:{calculate}\:\:\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{4}}}…
Question Number 41845 by maxmathsup by imad last updated on 13/Aug/18 $$\left.\mathrm{1}\right){find}\:\:\:\:\int\:\:\:\:\:\:\:\:\:\frac{{x}}{\:\sqrt{\mathrm{1}+{x}}\:+\sqrt{\mathrm{1}−{x}}}\:{dx} \\ $$$$\left.\mathrm{2}\right)\:{calculate}\:\:\int_{\mathrm{1}} ^{\mathrm{3}} \:\:\:\:\:\frac{{x}}{\:\sqrt{\mathrm{1}+{x}}\:+\sqrt{\mathrm{1}−{x}}}\:{dx} \\ $$ Answered by MJS last updated on 13/Aug/18…
Question Number 172899 by mathlove last updated on 03/Jul/22 $$\int_{\mathrm{0}} ^{\infty} {e}^{−{e}^{{x}} } \sqrt{{x}}\:{dx}=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 107342 by mnjuly1970 last updated on 10/Aug/20 $$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathscr{E}{valuate}: \\ $$$$\:\:\:\:\:\:\:\chi:=\int_{\mathrm{0}} ^{\:\frac{\pi}{\mathrm{4}}} {x}^{\mathrm{2}} {tan}\left({x}\right){dx}=\:???\: \\ $$$$\:\:\:\:\:\:\:\:\:\:\bigstar{prepared}\:{by}:\bigstar \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\clubsuit\clubsuit\clubsuit\:\:\:\mathscr{M}.\mathscr{N}\:\clubsuit\clubsuit\clubsuit \\ $$$$ \\ $$ Answered by…
Question Number 41806 by Raj Singh last updated on 13/Aug/18 Commented by prof Abdo imad last updated on 13/Aug/18 $${let}\:{A}\:=\:\int\:\:\frac{{arcsin}\left(.\sqrt{{x}}\right)−{arccos}\left(\sqrt{{x}}\right)}{{arcsin}\sqrt{{x}}\:+{arccos}\sqrt{{x}}}\:{dx} \\ $$$$\left.{arcosx}\:+{arcsinx}\right)^{'} =−\frac{\mathrm{1}}{\:\sqrt{\mathrm{1}−{x}^{\mathrm{2}} }}\:+\frac{\mathrm{1}}{\:\sqrt{\mathrm{1}−{x}^{\mathrm{2}} }}\:{for}…
Question Number 172872 by mnjuly1970 last updated on 02/Jul/22 $$ \\ $$$$\:\:\:\:\:\mathrm{lim}_{\:{x}\rightarrow\:\mathrm{0}^{+} } \left({x}^{\:\frac{\mathrm{1}}{\mathrm{l}{n}\left({xsin}\left({x}^{\mathrm{3}} \right)\right)}} \right)=? \\ $$$$ \\ $$$$ \\ $$ Answered by mnjuly1970…
Question Number 107314 by bemath last updated on 10/Aug/20 $$\:\:\:\:\:\:\:\:\doublebarwedge{bemath}\doublebarwedge \\ $$$$\:\:\:\:\:\underset{\mathrm{0}} {\overset{\mathrm{2}\pi} {\int}}\:\mathrm{ln}\:\left(\mathrm{1}+\mathrm{sin}\:{x}\right)\:{dx}\:? \\ $$ Answered by mnjuly1970 last updated on 10/Aug/20 $$\Omega=\int_{\mathrm{0}} ^{\:\mathrm{2}\pi}…
Question Number 172847 by Mikenice last updated on 02/Jul/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 41762 by math khazana by abdo last updated on 12/Aug/18 $${let}\:{f}\left({x}\right)\:=\:\int_{\mathrm{0}} ^{\mathrm{1}} \:\:\frac{{ln}\left(\mathrm{1}+{xt}^{\mathrm{2}} \right)}{\mathrm{1}+{t}^{\mathrm{2}} }\:{dt} \\ $$$$\left.\mathrm{1}\right)\:{find}\:{a}\:{simple}\:{form}\:{of}\:{f}\left({x}\right) \\ $$$$\left.\mathrm{2}\right)\:{calculate}\:\:\int_{\mathrm{0}} ^{\mathrm{1}} \:\:\frac{{ln}\left(\mathrm{1}+{t}^{\mathrm{2}} \right)}{\mathrm{1}+{t}^{\mathrm{2}} }{dt}…
Question Number 107291 by mathmax by abdo last updated on 09/Aug/20 $$\mathrm{let}\:\mathrm{x}\in\mathrm{R}−\left\{\mathrm{1},−\mathrm{1}\right\}\:\mathrm{explicit}\:\mathrm{the}\:\mathrm{function} \\ $$$$\mathrm{f}\left(\mathrm{x}\right)\:=\int_{\mathrm{0}} ^{\mathrm{2}\pi} \:\mathrm{ln}\left(\mathrm{x}^{\mathrm{2}} −\mathrm{2xcos}\theta\:+\mathrm{1}\right)\mathrm{d}\theta \\ $$$$ \\ $$ Answered by Ar Brandon…