Category: Integration

Question Number 170725 by Sotoberry last updated on 29/May/22 Answered by FelipeLz last updated on 30/May/22 $$u={\tan }^{-1}\left(x\right)\Rightarrow du=\frac{1}{1+x^2}dx$$$$dv=1dx\Rightarrow v=x$$$$\int\mathrm{tan}^{−\mathrm{1}} \left({x}\right){dx} \…

Question Number 170722 by Sotoberry last updated on 29/May/22 Answered by MikeH last updated on 29/May/22 $$u=\sin \theta$$$$du=\cos \theta d\theta$$$$dv=e^{\theta }d\theta$$$${v}\:=\:{e}^{\theta} \…

Question Number 170663 by kndramaths last updated on 28/May/22 Commented by kaivan.ahmadi last updated on 28/May/22 $$a.$$$$0⩽x⩽a,0⩽y⩽\sqrt{a^2-x^2}$$$$\int\frac{{dx}}{{a}^{\mathrm{2}} +{x}^{\mathrm{2}} }{dx}=\frac{\mathrm{1}}{{a}}{arctg}\left(\frac{{x}}{{a}}\right)…

Question Number 170593 by 119065 last updated on 27/May/22 Commented by mkam last updated on 27/May/22 $$\int (x+3-3){(x+3)}^{\frac{1}{2}}dx=\int {(x+3)}^{\frac{3}{2}}-3{(x+3)}^{\frac{1}{2}}dx$$$$$$$$=\:\frac{\mathrm{2}}{\mathrm{5}}\:\left({x}+\mathrm{3}\right)^{\frac{\mathrm{5}}{\mathrm{2}}} \:−\:\mathrm{2}\:\left({x}+\mathrm{3}\right)^{\frac{\mathrm{3}}{\mathrm{2}}}…

Question Number 170590 by rs4089 last updated on 27/May/22 Commented by rs4089 last updated on 27/May/22 $$solvethisorexpressinseriesof$$$$bernloullisnumbers$$ Terms of Service Privacy…