Category: Integration

Question Number 104104 by bemath last updated on 19/Jul/20 $$\int \frac{x{\tan }^{-1}\left(x\right)}{\sqrt{1+x^2}}dx?$$ Answered by OlafThorendsen last updated on 19/Jul/20 $$\mathrm{By}\mathrm{parts}:$$$$\sqrt{\mathrm{1}+{x}^{\mathrm{2}} }\mathrm{arctan}{x}−\int\sqrt{\mathrm{1}+{x}^{\mathrm{2}}…

Question Number 38516 by rahul 19 last updated on 26/Jun/18 $${\int }_0^{\frac{\pi }{2}}\mid \sin x-\cos x\mid \mathrm{d}x$$ Commented by math khazana by abdo last updated on 27/Jun/18…

Question Number 169563 by cortano1 last updated on 03/May/22 Commented by infinityaction last updated on 03/May/22 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 169548 by mathlove last updated on 02/May/22 Commented by infinityaction last updated on 02/May/22 $$\int \frac{x}{2\cos {}^{2}x/2}dx+\int \frac{2\sin x/2\cos x/2}{2\cos {}^{2}x/2}dx$$$$\underset{byparts}{\underbrace{\frac{1}{2}\int x\sec {}^{2}x/2dx}}+\int \tan x/2dx$$$${be}\:{continued}…

Question Number 38470 by maxmathsup by imad last updated on 25/Jun/18 $$calculatef\left(t\right)={\int }_0^{\mathrm{\infty }}\frac{cos\left(tx\right)}{{(1+{tx}^2)}^2}dxwitht⩾0$$$$\left.\mathrm{2}\right)\:{find}\:{the}\:{values}\:{of}\:\int_{\mathrm{0}} ^{\infty} \:\:\frac{{cos}\left(\mathrm{2}{x}\right)}{\left(\mathrm{1}+\mathrm{2}{x}^{\mathrm{2}} \right)^{\mathrm{2}} }{dx}\:\:{and}\:\int_{\mathrm{0}} ^{\infty} \:\:\:\frac{{cosx}}{\left(\mathrm{2}+{x}^{\mathrm{2}} \right)^{\mathrm{2}}…