Question Number 102606 by bemath last updated on 10/Jul/20 $${what}\:{is}\:{the}\:{volume}\:{of}\:{region} \\ $$$${bounded}\:{by}\:{y}\:={x}^{\mathrm{2}} −\mathrm{2}{x}\:{and} \\ $$$${y}={x}\:{that}\:{is}\:{rotated}\:{about} \\ $$$${y}=\mathrm{4}\:? \\ $$ Commented by bemath last updated on…
Question Number 37071 by math khazana by abdo last updated on 08/Jun/18 $${find}\:{the}\:{value}\:{of}\:\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}} \:\:\:\frac{{xdx}}{\mathrm{1}+{cosx}} \\ $$ Commented by math khazana by abdo last updated…
Question Number 37067 by math khazana by abdo last updated on 08/Jun/18 $${find}\:\int\:\:\:\:\:\frac{{dx}}{\left({x}+\mathrm{1}\right)\sqrt{\mathrm{1}+{x}^{\mathrm{2}} }} \\ $$ Commented by math khazana by abdo last updated on…
Question Number 37036 by ajfour last updated on 08/Jun/18 $$\int_{\mathrm{0}} ^{\:\:{a}} \left(\mathrm{1}−\frac{{b}−{x}}{\:\sqrt{\left({b}−{x}\right)^{\mathrm{2}} +{cx}}}\right)\:{dx}\:=\:? \\ $$ Commented by math khazana by abdo last updated on 09/Jun/18…
Question Number 37028 by nishant last updated on 08/Jun/18 $$\int\frac{\mathrm{2}{x}−\mathrm{1}}{\mathrm{5}{x}^{\mathrm{2}} −{x}+\mathrm{2}}\:{dx}\:\:=\:\:? \\ $$ Answered by ajfour last updated on 08/Jun/18 $${I}=\frac{\mathrm{1}}{\mathrm{5}}\int\frac{\mathrm{10}{x}−\mathrm{1}}{\mathrm{5}{x}^{\mathrm{2}} −{x}+\mathrm{2}}{dx}\:−\frac{\mathrm{4}}{\mathrm{25}}\int\frac{{dx}}{\left({x}−\frac{\mathrm{1}}{\mathrm{10}}\right)^{\mathrm{2}} +\frac{\mathrm{2}}{\mathrm{5}}−\frac{\mathrm{1}}{\mathrm{100}}} \\ $$$$\:\:=\frac{\mathrm{1}}{\mathrm{5}}\mathrm{ln}\:\mid\mathrm{5}{x}^{\mathrm{2}}…
Question Number 102555 by Dwaipayan Shikari last updated on 09/Jul/20 $$\int_{\mathrm{0}} ^{\mathrm{1}} \frac{{x}^{\mathrm{98}} −\mathrm{99}{x}+\mathrm{98}}{{logx}}{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 37018 by behi83417@gmail.com last updated on 08/Jun/18 Commented by math khazana by abdo last updated on 08/Jun/18 $$\left.\mathrm{1}\right)\:{let}\:{I}\:=\:\int\:\:\:\frac{\sqrt{\mathrm{1}+{x}^{\mathrm{2}} }}{\mathrm{1}+{x}}{dx}\:{changement}\:{x}={sht}\:{give} \\ $$$${I}\:=\:\int\:\:\:\:\frac{{ch}\left({t}\right)}{\mathrm{1}+{sh}\left({t}\right)}{ch}\left({t}\right){dt}=\:\int\:\:\:\frac{{ch}^{\mathrm{2}} \left({t}\right){dt}}{\mathrm{1}+{sh}\left({t}\right)} \\…
Question Number 37004 by behi83417@gmail.com last updated on 07/Jun/18 Answered by tanmay.chaudhury50@gmail.com last updated on 07/Jun/18 $$\int\frac{\sqrt{\mathrm{1}+{x}^{{p}} \:\:}}{{x}}{dx} \\ $$$$\int\frac{\mathrm{1}+{x}^{{p}} }{{x}\sqrt{\mathrm{1}+{x}^{{p}} \:}}{dx} \\ $$$$\int\frac{{x}^{{p}−\mathrm{1}} \left(\mathrm{1}+{x}^{{p}}…
Question Number 36997 by rahul 19 last updated on 07/Jun/18 $$\int\:\sqrt{\frac{\mathrm{1}+{x}}{{x}}\:}{dx}\:=\:? \\ $$ Commented by behi83417@gmail.com last updated on 07/Jun/18 $${x}={tg}^{\mathrm{2}} {t}\Rightarrow{dx}=\mathrm{2}{tgt}\left(\mathrm{1}+{tg}^{\mathrm{2}} {t}\right){dt} \\ $$$${I}=\int\sqrt{\frac{\mathrm{1}+{tg}^{\mathrm{2}}…
Question Number 36957 by rahul 19 last updated on 07/Jun/18 $$\mathrm{Interval}\:\mathrm{in}\:\mathrm{which}\:\mathrm{given}\:\mathrm{function}\:\mathrm{is} \\ $$$${decreasing}. \\ $$$$\mathrm{f}\left({x}\right)=\:\left(\mathrm{2}^{{x}} −\mathrm{1}\right)\left(\mathrm{2}^{{x}} −\mathrm{2}\right)^{\mathrm{2}} \\ $$ Answered by tanmay.chaudhury50@gmail.com last updated on…