Question Number 102397 by M±th+et+s last updated on 08/Jul/20 $$\int{ln}\left({x}−\sqrt{{x}}+\mathrm{1}\right){dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 167922 by peter frank last updated on 29/Mar/22 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\:\mathrm{Q}\:\:\mathrm{if} \\ $$$$\int_{\mathrm{0}} ^{\mathrm{Q}} \sqrt{\mathrm{cosec}\:\theta−\mathrm{1}}\:\mathrm{d}\theta=\mathrm{ln}\:\left(\frac{\mathrm{3}+\mathrm{2}\sqrt{\mathrm{2}}}{\mathrm{2}}\right) \\ $$$$ \\ $$ Commented by MJS_new last updated on…
Question Number 102383 by Dwaipayan Shikari last updated on 08/Jul/20 $$\int\frac{{x}}{{sin}^{\mathrm{2}} {x}−\mathrm{3}} \\ $$ Commented by Dwaipayan Shikari last updated on 08/Jul/20 $${I}\:{have}\:{done}\:{so}\:{far}.{This}\:{was}\:{an}\:{old}\:{unanswered}\:{question} \\ $$…
Question Number 102381 by Dwaipayan Shikari last updated on 08/Jul/20 $$\int\frac{{x}\sqrt{\mathrm{6}}{sec}^{\mathrm{2}} \frac{{x}}{\mathrm{2}}}{\mathrm{1}+\mathrm{9}{tan}^{\mathrm{4}} \frac{{x}}{\mathrm{2}}+\mathrm{18}{tan}^{\mathrm{2}} \frac{{x}}{\mathrm{2}}}{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 167912 by mathlove last updated on 29/Mar/22 $$\underset{\mathrm{0}} {\int}^{\frac{\pi}{\mathrm{4}}} \frac{{cos}\left(\mathrm{12}{x}\right)}{{cos}^{\mathrm{14}} \left({x}\right)}{dx}=? \\ $$ Answered by saboorhalimi last updated on 30/Mar/22 $$\mathrm{check}\:\mathrm{out}\:\mathrm{my}\:\mathrm{solution} \\ $$…
Question Number 102366 by bobhans last updated on 08/Jul/20 $$\underset{\mathrm{0}} {\overset{\pi/\mathrm{2}} {\int}}\:\frac{\mathrm{cos}\:{x}}{\mathrm{1}+\mathrm{cos}\:{x}+\mathrm{sin}\:{x}}\:{dx}\:? \\ $$ Answered by PRITHWISH SEN 2 last updated on 08/Jul/20 $$\mathrm{I}=\int_{\mathrm{0}} ^{\frac{\pi}{\mathrm{2}}}…
Question Number 102369 by bobhans last updated on 08/Jul/20 $${find}\:{the}\:{area}\:{bounded}\:{inner}\:{the}\:{curve} \\ $$$${r}\:=\:\mathrm{4}−\mathrm{2cos}\:\theta\:{and}\:{outer}\:{the}\:{curve}\:{r}\:=\:\mathrm{6}+\mathrm{2cos}\:\theta \\ $$ Answered by Ar Brandon last updated on 08/Jul/20 $$\mathrm{Area}\:,\:\mathrm{A}=\int_{\mathrm{0}} ^{\mathrm{2}\pi} \int_{\mathrm{4}−\mathrm{2cos}\theta}…
Question Number 36818 by maxmathsup by imad last updated on 06/Jun/18 $${find}\:{f}\left({a}\right)\:=\:\int\:\:\:\:\:\frac{{dx}}{\:\sqrt{\mathrm{1}−{ax}^{\mathrm{2}} }}\:\:{with}\:{a}\:{from}\:{R}\:. \\ $$ Commented by prof Abdo imad last updated on 06/Jun/18 $${case}\:\mathrm{1}\:\:{a}>\mathrm{0}\:\:{changement}\:\sqrt{{a}}{x}=\:{sint}\:{give}…
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Question Number 36811 by rahul 19 last updated on 05/Jun/18 $$\int\:\frac{\mathrm{sin}\:{x}}{\mathrm{cos}\:^{\mathrm{2}} {x}.\:\sqrt{\mathrm{cos}\:\mathrm{2}{x}}}\:{dx}=\:? \\ $$ Answered by MJS last updated on 05/Jun/18 $$\int\frac{\mathrm{sin}\:{x}}{\mathrm{cos}^{\mathrm{2}} \:{x}\:\sqrt{\mathrm{cos}\:\mathrm{2}{x}}}{dx}=\int\frac{\mathrm{sin}\:{x}}{\mathrm{cos}^{\mathrm{2}} \:{x}\:\sqrt{\mathrm{cos}^{\mathrm{2}} \:{x}\:−\mathrm{sin}^{\mathrm{2}}…