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Category: Integration

e-ax-b-dx-

Question Number 102043 by Dwaipayan Shikari last updated on 06/Jul/20 $$\int{e}^{\sqrt{{ax}+{b}}} {dx} \\ $$ Commented by Dwaipayan Shikari last updated on 06/Jul/20 $$\frac{\mathrm{2}}{{a}}\int{e}^{{u}} {udu}\:\:\:\:\:\:\:\:\:\:\:\:\:\left\{{suppose}\:{ax}+{b}={u}^{\mathrm{2}} \right.…

Question-36491

Question Number 36491 by rahul 19 last updated on 02/Jun/18 Answered by MJS last updated on 08/Jun/18 $$\mathrm{just}\:\mathrm{differentiate}\:\mathrm{the}\:\mathrm{following}\:\mathrm{term}: \\ $$$$\pm\frac{\mathrm{1}}{\left(\mathrm{sec}\:{x}\:+\mathrm{tan}\:{x}\right)^{\frac{\mathrm{11}}{\mathrm{2}}} }\left(\frac{\mathrm{1}}{\mathrm{11}}\pm\frac{\mathrm{1}}{\mathrm{7}}\left(\mathrm{sec}\:{x}\:+\mathrm{tan}\:{x}\right)^{\mathrm{2}} \right) \\ $$$$\mathrm{write}\:\mp\:\mathrm{for}\:\mathrm{changing}\:\mathrm{signs}.\:\mathrm{it}'\mathrm{s}\:\mathrm{faster} \\…

evaluate-cos-3-xsin-3-xdx-

Question Number 102001 by hardylanes last updated on 06/Jul/20 $${evaluate}\:\int\mathrm{cos}\:^{\mathrm{3}} {x}\mathrm{sin}\:^{\mathrm{3}} {xdx}. \\ $$ Answered by bobhans last updated on 06/Jul/20 $$\int\:\left(\mathrm{1}−\mathrm{sin}\:^{\mathrm{2}} {x}\right)\:\mathrm{sin}\:^{\mathrm{3}} {x}\:{d}\left(\mathrm{sin}\:{x}\right)\:=\: \\…

e-tan-sec-sin-d-

Question Number 36459 by rahul 19 last updated on 02/Jun/18 $$\int\:\mathrm{e}^{\mathrm{tan}\:\theta} \left(\mathrm{sec}\:\theta\:−\mathrm{sin}\:\theta\right)\:\mathrm{d}\theta\:=\:? \\ $$ Answered by ajfour last updated on 02/Jun/18 $${let}\:\mathrm{tan}\:\theta={t} \\ $$$$\Rightarrow\:{I}=\int{e}^{{t}} \left(\mathrm{sec}\:\theta−\mathrm{sin}\:\theta\right)\mathrm{cos}\:^{\mathrm{2}}…

dx-2x-7-x-3-x-4-

Question Number 36444 by rahul 19 last updated on 02/Jun/18 $$\int\:\frac{\mathrm{d}{x}}{\left(\mathrm{2}{x}−\mathrm{7}\right)\sqrt{\left({x}−\mathrm{3}\right)\left({x}−\mathrm{4}\right)}}\:=\:? \\ $$ Commented by math1967 last updated on 02/Jun/18 $${let}\mathrm{2}{x}−\mathrm{7}=\frac{\mathrm{1}}{{z}}\:\:\therefore\mathrm{2}{dx}=−\frac{{dz}}{{z}^{\mathrm{2}} } \\ $$$$−\int\frac{{dz}}{\mathrm{2}{z}^{\mathrm{2}} ×\frac{\mathrm{1}}{{z}}\sqrt{\frac{\left(\mathrm{1}+{z}\right)}{\mathrm{2}{z}}×\frac{\left(\mathrm{1}−{z}\right)}{\mathrm{2}{z}}}}…