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Category: Integration

let-give-I-0-dx-x-2-i-2-1-extract-Re-I-and-Im-I-2-find-the-value-of-I-3-calculate-Re-I-and-Im-I-

Question Number 36167 by abdo mathsup 649 cc last updated on 29/May/18 $${let}\:{give}\:\:{I}\:\:=\:\int_{\mathrm{0}} ^{\infty} \:\:\:\frac{{dx}}{\left({x}^{\mathrm{2}} \:+{i}\right)^{\mathrm{2}} } \\ $$$$\left.\mathrm{1}\right)\:{extract}\:{Re}\left({I}\right)\:{and}\:{Im}\left({I}\right) \\ $$$$\left.\mathrm{2}\right)\:{find}\:{the}\:{value}\:{of}\:{I} \\ $$$$\left.\mathrm{3}\right)\:{calculate}\:{Re}\left({I}\right)\:{and}\:{Im}\left({I}\right)\:. \\ $$…

sin-3-3x-cos-4-5x-dx-

Question Number 167223 by cortano1 last updated on 10/Mar/22 $$\:\:\int\:\mathrm{sin}\:^{\mathrm{3}} \left(\mathrm{3x}\right)\:\mathrm{cos}\:^{\mathrm{4}} \left(\mathrm{5x}\right)\:\mathrm{dx}=? \\ $$ Commented by greogoury55 last updated on 10/Mar/22 $$\:\mathrm{sin}\:^{\mathrm{3}} \left(\mathrm{3}{x}\right)=\frac{\mathrm{3sin}\:\left(\mathrm{3}{x}\right)−\mathrm{sin}\:\left(\mathrm{9}{x}\right)}{\mathrm{4}} \\ $$$$\:\mathrm{cos}\:^{\mathrm{4}}…

2-1-e-t-2-t-2-dt-

Question Number 167173 by metamorfose last updated on 08/Mar/22 $$\int_{−\mathrm{2}} ^{−\mathrm{1}} {e}^{−\frac{{t}}{\mathrm{2}}} \sqrt{{t}+\mathrm{2}}\:{dt}\:=\:??? \\ $$ Answered by metamorfose last updated on 08/Mar/22 $${let}\:{I}=\int_{−\mathrm{2}} ^{−\mathrm{1}} {e}^{−\frac{{t}}{\mathrm{2}}}…

x-x-x-x-x-x-dx-

Question Number 101633 by student work last updated on 03/Jul/20 $$\int\mathrm{x}^{\mathrm{x}^{\mathrm{x}} } \centerdot\mathrm{x}^{\mathrm{x}} \centerdot\mathrm{x}\:\mathrm{dx}=? \\ $$ Commented by Tinku Tara last updated on 03/Jul/20 $$\mathrm{Please}\:\mathrm{post}\:\mathrm{questions}\:\mathrm{where}\:\mathrm{you}…

0-pi-2-ln-ln-2-sin-pi-2-ln-2-sin-ln-cos-tan-d-

Question Number 101608 by  M±th+et+s last updated on 03/Jul/20 $$\int_{\mathrm{0}\:} ^{\frac{\pi}{\mathrm{2}}} {ln}\left(\frac{{ln}^{\mathrm{2}} \left({sin}\left(\theta\right)\right)}{\pi^{\mathrm{2}} +{ln}^{\mathrm{2}} \left({sin}\left(\theta\right)\right)}\right)\frac{{ln}\left({cos}\left(\theta\right)\right)}{{tan}\left(\theta\right)}{d}\theta \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com