Question Number 101808 by Ar Brandon last updated on 04/Jul/20 $$\int_{\frac{\mathrm{1}}{\mathrm{3}}} ^{\mathrm{1}} \frac{\left(\mathrm{x}−\mathrm{x}^{\mathrm{3}} \right)^{\mathrm{1}/\mathrm{3}} }{\mathrm{x}^{\mathrm{4}} }\mathrm{dx} \\ $$ Answered by Dwaipayan Shikari last updated on…
Question Number 167328 by cortano1 last updated on 13/Mar/22 $$\:\:\:\:\:\:\int_{\mathrm{0}} ^{\:\pi/\mathrm{2}} \:\frac{\mathrm{cos}\:{x}+\mathrm{cos}\:^{\mathrm{5}} {x}\:\mathrm{sin}\:{x}}{\:\sqrt{\mathrm{1}+\mathrm{cos}\:^{\mathrm{2}} {x}}}\:{dx}\:=? \\ $$ Answered by MJS_new last updated on 13/Mar/22 $$\int\frac{\mathrm{cos}\:{x}\:+\mathrm{cos}^{\mathrm{5}} \:{x}\:\mathrm{sin}\:{x}}{\:\sqrt{\mathrm{1}+\mathrm{cos}^{\mathrm{2}}…
Question Number 101793 by Dwaipayan Shikari last updated on 04/Jul/20 $$\int_{\mathrm{1}} ^{\mathrm{2}} \frac{{logu}}{\left(\sqrt{{u}−\mathrm{1}}\right)\left(\sqrt{{u}−\mathrm{1}}+\mathrm{1}\right)}{du} \\ $$ Answered by mathmax by abdo last updated on 05/Jul/20 $$\mathrm{I}\:=\int_{\mathrm{1}}…
Question Number 101791 by Dwaipayan Shikari last updated on 04/Jul/20 $$\frac{\mathrm{1}}{{n}^{\mathrm{3}\:\:} }\underset{{n}\rightarrow\infty} {\mathrm{lim}}\left({ne}^{−\left(\frac{\mathrm{1}}{{n}}\right)^{\mathrm{2}} } +\mathrm{2}{ne}^{−\left(\frac{\mathrm{2}}{{n}}\right)^{\mathrm{2}} } +….\infty\right) \\ $$ Answered by Ar Brandon last updated…
Question Number 101783 by I want to learn more last updated on 04/Jul/20 $$\int_{\:\mathrm{0}} ^{\:\mathrm{1}} \:\:\frac{\mathrm{ln}\left(\mathrm{x}^{\mathrm{2}} \:+\:\mathrm{1}\right)}{\mathrm{x}\:\:+\:\:\mathrm{1}} \\ $$ Answered by mathmax by abdo last…
Question Number 167318 by cortano1 last updated on 13/Mar/22 $$\:\:\:\:\:\:\int\:\frac{\mathrm{dx}}{\:\sqrt{\mathrm{x}+\sqrt[{\mathrm{3}}]{\mathrm{x}}}}\:=? \\ $$ Answered by bobhans last updated on 14/Mar/22 Terms of Service Privacy Policy Contact:…
Question Number 167312 by cortano1 last updated on 12/Mar/22 $$\:\:\:\:\:\:\:\int\:\frac{\mathrm{sin}\:^{\mathrm{3}} \mathrm{x}+\mathrm{1}}{\mathrm{sin}\:^{\mathrm{2}} \mathrm{x}−\mathrm{1}}\:\mathrm{dx}\:=? \\ $$ Commented by Florian last updated on 10/Apr/22 $$\:\:{Simplify}:\:\frac{{sin}^{\mathrm{3}} {x}+\mathrm{1}}{{sin}^{\mathrm{2}} −\mathrm{1}}=\frac{{sin}^{\mathrm{2}} \left({x}\right)−{sin}\left({x}\right)+\mathrm{1}}{{sin}\left({x}\right)−\mathrm{1}}…
Question Number 101775 by Study last updated on 04/Jul/20 $$\int{x}^{{x}^{{x}} } \centerdot{x}^{{x}} \centerdot{xdx}=? \\ $$$${or}\:{it}\:{able}\:{to}\:{solve}? \\ $$ Commented by mr W last updated on 04/Jul/20…
Question Number 167310 by amin96 last updated on 12/Mar/22 $$\boldsymbol{\mathrm{NICE}}\:\boldsymbol{\mathrm{CALCULUS}} \\ $$$$\int_{\mathrm{0}} ^{\mathrm{1}} \frac{\boldsymbol{\mathrm{ln}}\left(\mathrm{1}−\boldsymbol{\mathrm{x}}\right)\boldsymbol{\mathrm{ln}}\left(\mathrm{1}−\frac{\boldsymbol{\mathrm{x}}}{\mathrm{2}}\right)}{\boldsymbol{\mathrm{x}}}\boldsymbol{\mathrm{dx}}=? \\ $$$$ \\ $$$$ \\ $$ Terms of Service Privacy Policy…
Question Number 167305 by greogoury55 last updated on 12/Mar/22 $$\:\:\:{Q}=\int\:\frac{\mathrm{2sin}\:\left({x}\right)}{\:\sqrt{\mathrm{3}}\:\mathrm{sin}\:\left({x}\right)−\mathrm{cos}\:\left({x}\right)}\:{dx}=? \\ $$ Answered by amin96 last updated on 13/Mar/22 $${Q}=\int\frac{{sin}\left({x}\right)}{\frac{\sqrt{\mathrm{3}}}{\mathrm{2}}{sin}\left({x}\right)−\frac{\mathrm{1}}{\mathrm{2}}{cos}\left({x}\right)}{dx}= \\ $$$$=−\int\frac{{sin}\left({x}\right)}{{sin}\left(\frac{\pi}{\mathrm{6}}−{x}\right)}{dx}\:\:\:\:\:\:\:\:\frac{\pi}{\mathrm{6}}−{x}\:={t} \\ $$$${x}=\frac{\pi}{\mathrm{6}}−{t}\:\:\:\:\:{Q}=\int\frac{{sin}\left(\frac{\pi}{\mathrm{6}}−{t}\right)}{{sin}\left({t}\right)}{dt}= \\…