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Category: Integration

sin-3-x-1-sin-2-x-1-dx-

Question Number 167312 by cortano1 last updated on 12/Mar/22 sin3x+1sin2x1dx=? Commented by Florian last updated on 10/Apr/22 $$\:\:{Simplify}:\:\frac{{sin}^{\mathrm{3}} {x}+\mathrm{1}}{{sin}^{\mathrm{2}} −\mathrm{1}}=\frac{{sin}^{\mathrm{2}} \left({x}\right)−{sin}\left({x}\right)+\mathrm{1}}{{sin}\left({x}\right)−\mathrm{1}}…