Question Number 101079 by I want to learn more last updated on 30/Jun/20 Commented by I want to learn more last updated on 30/Jun/20 $$\mathrm{Expecially}\:\mathrm{question}\:\left(\mathrm{2}\right)\:\mathrm{please}…
Question Number 35541 by tanmay.chaudhury50@gmail.com last updated on 20/May/18 Commented by tanmay.chaudhury50@gmail.com last updated on 20/May/18 $${i}\:{am}\:{sharing}\:{some}\:{formula}… \\ $$ Commented by NECx last updated on…
Question Number 166614 by qaz last updated on 23/Feb/22 $$\mathrm{calculate}::\:\:\:\int_{\mathrm{0}} ^{\infty} \frac{\left\{\mathrm{x}\right\}^{\mathrm{2}} \left(\mathrm{1}−\left\{\mathrm{x}\right\}\right)^{\mathrm{2}} }{\left(\mathrm{1}+\mathrm{x}\right)^{\mathrm{5}} }=\frac{\mathrm{7}}{\mathrm{12}}−\gamma \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 101073 by Dwaipayan Shikari last updated on 30/Jun/20 $$\int_{\mathrm{0}} ^{\infty} \frac{{sin}\left({logx}\right)}{{logx}}{dx} \\ $$ Answered by mathmax by abdo last updated on 30/Jun/20 $$\mathrm{A}\:=\int_{\mathrm{0}}…
Question Number 166610 by cortano1 last updated on 23/Feb/22 $$\:\:\:\:\int\:\frac{\mathrm{x}^{\mathrm{2}} +\mathrm{3}}{\mathrm{x}^{\mathrm{4}} +\mathrm{5x}^{\mathrm{2}} +\mathrm{9}}\:\mathrm{dx}\:? \\ $$ Commented by MJS_new last updated on 23/Feb/22 $$\mathrm{in}\:\mathrm{this}\:\mathrm{case}: \\ $$$$\frac{{d}}{{dx}}\left[\frac{\mathrm{1}}{{a}}\mathrm{arctan}\:\frac{{ax}}{{b}−{x}^{\mathrm{2}}…
Question Number 101057 by bemath last updated on 30/Jun/20 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{area}\:\mathrm{bounded}\:\mathrm{the}\: \\ $$$$\mathrm{curves}\:\mathrm{f}\left(\mathrm{x}\right)=\:\mid{x}^{\mathrm{3}} −\mathrm{4}{x}^{\mathrm{2}} +\mathrm{3}{x}\mid\:\mathrm{and}\: \\ $$$$\mathrm{x}−\mathrm{axis}\: \\ $$ Answered by john santu last updated on…
Question Number 166570 by cortano1 last updated on 22/Feb/22 Answered by bobhans last updated on 22/Feb/22 $$\:\mathrm{I}=\int\:\frac{\left(\mathrm{x}+\mathrm{1}\right)^{\mathrm{2}} +\mathrm{2}}{\left(\mathrm{x}+\mathrm{1}\right)\sqrt{\mathrm{x}^{\mathrm{2}} +\mathrm{1}}}\:\mathrm{dx}\:=\:\int\frac{\mathrm{x}+\mathrm{1}}{\:\sqrt{\mathrm{x}^{\mathrm{2}} +\mathrm{1}}}\mathrm{dx}+\int\frac{\mathrm{2}}{\left(\mathrm{x}+\mathrm{1}\right)\sqrt{\mathrm{x}^{\mathrm{2}} +\mathrm{1}}}\mathrm{dx} \\ $$$$\mathrm{I}_{\mathrm{1}} =\frac{\mathrm{1}}{\mathrm{2}}\int\:\frac{\mathrm{d}\left(\mathrm{x}^{\mathrm{2}} +\mathrm{1}\right)}{\:\sqrt{\mathrm{x}^{\mathrm{2}}…
Question Number 101018 by Dwaipayan Shikari last updated on 29/Jun/20 $$\int_{−\infty} ^{\infty} \frac{{log}\left({sin}^{\mathrm{2}} {x}\right)}{\mathrm{1}+{x}+{e}^{{x}} }{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 101023 by Dwaipayan Shikari last updated on 29/Jun/20 $$\int{tan}^{\frac{\mathrm{1}}{\mathrm{5}}} {x}\:{cotx}\:{secxdx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 166552 by cortano1 last updated on 22/Feb/22 $$\:\:\:\:\int_{−\infty} ^{\infty} \mathrm{cos}\:\left(\frac{\mathrm{1}}{\mathrm{2}}\pi\mathrm{x}\left(\mathrm{x}+\mathrm{1}\right)\right)\:\mathrm{sin}\:\left(\pi\mathrm{x}^{\mathrm{2}} \right)\:\mathrm{dx}\:=? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com