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Category: Integration

sin-4x-4sin-4-x-4sin-2-x-1-dx-

Question Number 167438 by cortano1 last updated on 16/Mar/22 sin4x4sin4x4sin2x+1dx=? Answered by MJS_new last updated on 16/Mar/22 $$\frac{\mathrm{sin}\:\mathrm{4}{x}}{\mathrm{1}−\mathrm{4sin}^{\mathrm{2}} \:{x}\:+\mathrm{4sin}^{\mathrm{4}} \:{x}}=\frac{\mathrm{2sin}\:\mathrm{4}{x}}{\mathrm{1}+\mathrm{cos}\:\mathrm{4}{x}}=\frac{\mathrm{2sin}\:\mathrm{2}{x}\:\mathrm{cos}\:\mathrm{2}{x}}{\mathrm{cos}^{\mathrm{2}} \:\mathrm{2}{x}}=…