Question Number 37307 by math khazana by abdo last updated on 11/Jun/18 $${calculate}\:\:\:\int_{\gamma} \:\:\:\:\frac{{dz}}{{z}}\:\:\:{with}\:\gamma\:=\left\{{z}\in{C}\:/\mid{z}\mid=\mathrm{1}\right\}\:. \\ $$ Commented by prof Abdo imad last updated on 15/Jun/18…
Question Number 37309 by math khazana by abdo last updated on 11/Jun/18 $${calculate}\:\:\int_{\mathrm{0}} ^{+\infty} \:\:\:\frac{{x}^{\mathrm{2}} }{\left(\mathrm{1}+{x}^{\mathrm{2}} \right)^{\mathrm{3}} }\:{dx}\:. \\ $$ Commented by abdo.msup.com last updated…
Question Number 37306 by math khazana by abdo last updated on 11/Jun/18 $${calculate}\:\int_{−\infty} ^{+\infty} \:\:\:{e}^{{ix}} \:\:\:\frac{{x}−{i}}{\left({x}+{i}\right)\left({x}^{\mathrm{2}} \:+\mathrm{3}\right)}\:{dx}\:. \\ $$$$ \\ $$ Commented by prof Abdo…
Question Number 37304 by math khazana by abdo last updated on 11/Jun/18 $${calculate}\:\int_{−\infty} ^{+\infty} \:\:\:\frac{\mathrm{5}+{e}^{{ix}} }{\left(\mathrm{3}+{e}^{{ix}} \right)\left(\mathrm{1}+{x}^{\mathrm{2}} \right)}{dx}\:. \\ $$ Commented by prof Abdo imad…
Question Number 37303 by math khazana by abdo last updated on 11/Jun/18 $${calculate}\:\:\int_{\gamma} \:\:\:\:\:\:\frac{{dz}}{{z}^{\mathrm{3}} \:+\mathrm{8}}\:{in}\:{those}\:{cases} \\ $$$$\left.\mathrm{1}\right)\:\gamma\:=\left\{{z}\in{C}\:/\:\mid{z}\mid\:=\mathrm{1}\right\} \\ $$$$\left.\mathrm{2}\right)\:\gamma\:=\left\{{z}\in{C}\:/\:\mid{z}\mid\:=\mathrm{3}\right\} \\ $$ Commented by prof Abdo…
Question Number 37302 by math khazana by abdo last updated on 11/Jun/18 $${let}\:\gamma\:=\:\left\{{z}\in{C}\:/\:\mid{z}\mid\:=\mathrm{4}\right\}\: \\ $$$${calculate}\:\:\int_{\gamma} \:\:\:\:\:\frac{{dz}}{{z}\:{sinz}}\:{in}\:{the}\:{positif}\:{sens}. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 37300 by math khazana by abdo last updated on 11/Jun/18 $${let}\:{f}\left({z}\right)=\frac{\left(\mathrm{1}−{z}^{\mathrm{2}} \right){e}^{\mathrm{2}{z}} }{{z}^{\mathrm{3}} } \\ $$$${calculate}\:{Res}\left({f},\:\mathrm{0}\right) \\ $$ Commented by prof Abdo imad…
Question Number 37301 by math khazana by abdo last updated on 11/Jun/18 $${find}?{the}\:{value}\:{of}\:\:\int_{−\infty} ^{+\infty} \:\:\:\frac{\left(\mathrm{2}{x}+\mathrm{1}\right){e}^{−{x}^{\mathrm{2}} } }{\mathrm{1}+\mathrm{4}{x}^{\mathrm{2}} }\:{dx}\:. \\ $$ Terms of Service Privacy Policy…
Question Number 168368 by SUPERMATH last updated on 09/Apr/22 Answered by qaz last updated on 09/Apr/22 $$\int\frac{\mathrm{x}^{\mathrm{2}} }{\:\sqrt{\mathrm{1}+\mathrm{x}+\mathrm{x}^{\mathrm{2}} }}\mathrm{dx}=\int\sqrt{\mathrm{1}+\mathrm{x}+\mathrm{x}^{\mathrm{2}} }−\frac{\mathrm{1}+\mathrm{x}}{\:\sqrt{\mathrm{1}+\mathrm{x}+\mathrm{x}^{\mathrm{2}} }}\mathrm{dx} \\ $$$$=\mathrm{x}\sqrt{\mathrm{1}+\mathrm{x}+\mathrm{x}^{\mathrm{2}} }−\int\frac{\mathrm{x}+\mathrm{2x}^{\mathrm{2}} }{\:\mathrm{2}\sqrt{\mathrm{1}+\mathrm{x}+\mathrm{x}^{\mathrm{2}}…
Question Number 37299 by math khazana by abdo last updated on 11/Jun/18 $${calculate}\:\:\int_{{C}} \:\:\:\frac{\mathrm{9}\left({z}^{\mathrm{2}} \:+\mathrm{2}\right)}{{z}\left({z}+\mathrm{1}\right)^{\mathrm{3}} \left({z}−\mathrm{2}\right)}{dz}\:\:{with}\:\:{C}\:{is}\:{the} \\ $$$${circle}\:{C}\:=\left\{{z}\in{C}/\:\mid{z}\mid\:=\mathrm{3}\right\}\: \\ $$ Commented by math khazana by…