Category: Integration

Question Number 35427 by abdo.msup.com last updated on 18/May/18 $$calculate{\int }_2^5\frac{e^{\sqrt{x+1}}}{\sqrt{x+1}}dx$$ Commented by prof Abdo imad last updated on 19/May/18 $${changement}\:\sqrt{{x}+\mathrm{1}}={t}\:{give}\:{x}={t}^{\mathrm{2}}…

Question Number 100956 by bobhans last updated on 29/Jun/20 Answered by john santu last updated on 29/Jun/20 $$\mathrm{set}\ln \left(\mathrm{x}\right)=\mathrm{z}\to \{\begin{array}{l}\mathrm{z}=1\\ \mathrm{z}=\mathrm{e}\end{array}$$$$\left.\mathrm{I}=\:\underset{\mathrm{1}} {\overset{\mathrm{e}} {\int}}\:\mathrm{ln}\left(\mathrm{z}\right).\:\mathrm{z}\:\mathrm{dz}\:=\:\frac{\mathrm{1}}{\mathrm{2}}\mathrm{z}^{\mathrm{2}} .\mathrm{ln}\left(\mathrm{z}\right)\right]_{\mathrm{1}} ^{\mathrm{e}} −\frac{\mathrm{1}}{\mathrm{2}}\overset{\mathrm{e}}…

Question Number 166488 by bobhans last updated on 21/Feb/22 $$\mathrm{B}=\int \sqrt{\frac{\sin 2\mathrm{x}-1}{\cos 2\mathrm{x}-1}}\mathrm{dx}=?$$ Answered by greogoury55 last updated on 21/Feb/22 $$B=\int \sqrt{\frac{1-\sin 2x}{1-\cos 2x}}dx$$$$\:\:\:{B}=\int\:\sqrt{\frac{\mathrm{sin}\:^{\mathrm{2}} {x}+\mathrm{cos}\:^{\mathrm{2}} {x}−\mathrm{2sin}\:{x}\:\mathrm{cos}\:{x}}{\mathrm{2sin}\:^{\mathrm{2}} {x}}}\:{dx}…

Question Number 166480 by amin96 last updated on 20/Feb/22 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 166449 by cortano1 last updated on 20/Feb/22 $$\mathrm{C}=\int \frac{1-\tan {}^2\mathrm{x}}{1+\sec {}^2\mathrm{x}}\mathrm{dx}=?$$ Commented by cortano1 last updated on 20/Feb/22 $$\mathrm{oo}\mathrm{yes}$$ Commented…