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Category: Integration

Question-65200

Question Number 65200 by rajesh4661kumar@gmail.com last updated on 26/Jul/19 Answered by ajfour last updated on 26/Jul/19 $${I}=\int\sqrt{\mathrm{tan}\:{x}}{dx} \\ $$$${let}\:\mathrm{tan}\:{x}={t}^{\mathrm{2}} \:\Rightarrow\:{dx}=\frac{\mathrm{2}{tdt}}{\mathrm{1}+{t}^{\mathrm{2}} } \\ $$$$\Rightarrow\:{I}=\int\frac{\mathrm{2}{t}^{\mathrm{2}} {dt}}{\mathrm{1}+{t}^{\mathrm{4}} }…