Question Number 99779 by john santu last updated on 23/Jun/20 Commented by Dwaipayan Shikari last updated on 23/Jun/20 $$\int{tan}^{\mathrm{6}} {xsec}^{\mathrm{2}} {xsec}^{\mathrm{2}} {xdx}=\int{t}^{\mathrm{6}} \left(\mathrm{1}+{t}^{\mathrm{2}} \right){dt}=\frac{{t}^{\mathrm{7}} }{\mathrm{7}}+\frac{{t}^{\mathrm{9}}…
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