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Category: Integration

Question-99326

Question Number 99326 by 175 last updated on 20/Jun/20 Answered by abdomathmax last updated on 20/Jun/20 atformofserie$$\mathrm{I}\:=\int\:\:\frac{\mathrm{e}^{\mathrm{2x}} \:\mathrm{e}^{−\mathrm{x}^{\mathrm{2}} −\mathrm{5x}−\mathrm{4}} }{\mathrm{1}−\mathrm{e}^{\mathrm{x}−\mathrm{x}^{\mathrm{2}} −\mathrm{5x}−\mathrm{4}} }\:\mathrm{dx}\:=\int\:\:\frac{\mathrm{e}^{−\mathrm{x}^{\mathrm{2}} −\mathrm{3x}−\mathrm{4}}…