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Category: Integration

Question-99168

Question Number 99168 by bemath last updated on 19/Jun/20 Answered by Kunal12588 last updated on 19/Jun/20 I=0π/2xcosx1+sin2xdx$$\Rightarrow{I}=\int_{\mathrm{0}} ^{\:\pi/\mathrm{2}} \:\frac{\left(\pi/\mathrm{2}\right)\mathrm{cos}\:{x}}{\mathrm{1}+\mathrm{sin}^{\mathrm{2}} \:{x}}{dx}−\int_{\mathrm{0}}…

24-2x-1-3-dx-

Question Number 164684 by Zaynal last updated on 20/Jan/22 24(2x1)3dx Answered by Ar Brandon last updated on 20/Jan/22 $$=\int\frac{\mathrm{24}}{\left(\mathrm{2}{x}−\mathrm{1}\right)^{\mathrm{3}} }{dx}=−\frac{\mathrm{6}}{\left(\mathrm{2}{x}−\mathrm{1}\right)^{\mathrm{2}} }+{C} \

8x-3-2x-dx-

Question Number 164681 by Zaynal last updated on 20/Jan/22 (8x32x)dx Answered by Ar Brandon last updated on 20/Jan/22 =4(32x3)32xdx$$=\mathrm{4}\int\left(\left(\mathrm{3}−\mathrm{2}{x}\right)^{\frac{\mathrm{3}}{\mathrm{2}}} −\mathrm{3}\left(\mathrm{3}−\mathrm{2}{x}\right)^{\frac{\mathrm{1}}{\mathrm{2}}} \right){dx}…